odness-of-fit test where all assumptions were met yielded the chi-square test statistic χ2=1.92 and a corresponding p-value of 0
1 answer:
Answer: hello the options related to your question is missing attached below are the options
answer : The researcher did not state that the p-value is conditional on the null hypothesis being true ( A )
Step-by-step explanation:
What is wrong with the researcher's interpretation is that the researcher did not state that the p-value is conditional on the null hypothesis being true.
The P-value is a required value when either rejecting or accepting the null hypothesis. and the researcher did not add the clause that the probability of getting a statistic > 1.92 provided the null hypothesis is assumed to be true
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Answer:
<em>$4.84</em>
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Step-by-step explanation:
Given that
For delivery within mi, charges = $1.25
For delivery within mi -
mi, charges = $1.70
For delivery within mi - 2 mi, charges = $2.15
and
so on.
i.e.
For delivery within 2 mi - 2 mi, charges = $2.60
For delivery within 2 mi - 2
mi, charges = $3.05
For delivery within 2 mi - 2
mi, charges = $3.50
For delivery within 2 mi - 3 mi, charges = $3.95
For delivery within 3 mi - 3 mi, charges = $4.40
So, every 0.25 mi or mi increase in distance, there is an increase of $0.45 in the charges.
It is given that there is increase of 10% in the rates.
i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.
The distance of miles lies within the range 3 mi - 3
mi.
So actual charges after increase of 10%