Y/x = 5 bc in order to isolate the variables you must divide by x on both sides to separate the 5, leaving you with y/x=5
8s-3s=5s
5s=110
Divide both sides by 5 => s=22
RZS = 3s = 3(22) = 66
TZS= 8s = 8(22) = 176
Let us assume the first number to be = x
Let us assume the second number to be = y
Then
x^2 - y^2 = 5
x^2 = y^2 + 5
And
3x^2 - 2y^2 = 19
Multiplying the first equation by -2, we get
- 2x^2 + 2y^2 = - 10
Now subtracting the two equations, we get
x^2 = 9
x = 3
Putting the value of "x" in the first equation, we get
(3)^2 - y^2 = 5
9 - y^2 = 5
y^2 = 4
y = 2
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
Answer:
the answer is 3
Step-by-step explanation:
because if you do the methoes method you know that it rules out 1 and 2 after you do that its just between 3 and 4, for the caunususicon there has to be one, that is why i think its 3. hope this helps!
Answer:
c ≥ 10 dozen
Step-by-step explanation:
Victor wants to have at least 10 dozen cookies for the bake sale.
In layman terms it can be understood as that Victor wants either 10 dozen cookies or more than that such as 11, 12, 13, 50 , 100 whatever number is greater than 10.
Let the no. of dozen of cookies wanted by him is c
according to condition
if victor wants either 10 dozen cookies
it can be represented mathematically as
c = 10 dozen (1)
_____________________________________
If victor wants no. of dozens of cookies greater than 10 .
it can be written as
c >10 dozen (2) (">" is symbol for greater than . expression simply means value of x should be greater than 10)
______________________________________________
now combining equation one and two, we have
c ≥ 10 dozen . It can means that x can take value starting from 10 to any no greater than..
