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wolverine [178]
3 years ago
8

Helpppp plssss :))))))((((

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

a= 80

b= .25

Step-by-step explanation:

We know that a has to equal 80 because

a(b)^0=80\\a=80

We can then just solve for b

80(b)^1=20\\b=\frac{20}{80} \\b=.25

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What is the solution to the following system of equations?
deff fn [24]

Answer:

D) x=-3, y=-7

Step-by-step explanation:

9x - 7y = 22

x + 3y= -24

9x - 7y = 22

x= -24-3y

9(-24-3y)-7y=22

x= -24-3y

-216-27y-7y=22

x= -24-3y

-34y=22+216

x= -24-3y

-34y=238

x= -24-3y

y=238/(-34)

x=-24-3y

y=-7

x=-24-3*(-7)

y=-7

x=-24+21

y=-7

x=-3

(x,y)=(-3,-7)

7 0
3 years ago
pencils are sold in packages of 10 and erasers are sold in packages of 6 what is the least number of pencils and erasers you can
pantera1 [17]
The first time 6 reaches a ten is 30, which is times 5, so 5 erasers, and then easily 3 pencils, so the least amount is 5 erasers and 3 pencils :)
4 0
3 years ago
PLEASE HELP! Dividing fractions!
gulaghasi [49]

-4/3 is your awnser i hope its corect



5 0
3 years ago
Find the measure for LQR.
Charra [1.4K]

Answer:

Option A

m\angle LQR=126^o

Step-by-step explanation:

step 1

Find the value of b

we know that

m\angle MQR=m\angle LQX ----> by vertical angles

substitute the given values

(-3b+63)^o=(90-12b)^o

solve for b

12b-3b=90-63\\9b=27\\b=3

step 2

Find the measure of angle LQR

we know that

m\angle LQR+m\angle MQR=180^o ---> by supplementary angles (form a linear pair)

m\angle MQR=(-3b+63)^o

substitute the value of b

m\angle MQR=(-3(3)+63)=54^o

substitute in the expression above

m\angle LQR+54^o=180^o

m\angle LQR=180^o-54^o=126^o

6 0
3 years ago
The contrapositive of p q is:
Kay [80]
Some symbols are missing. I'm assuming you meant to put in a horseshoe symbol like so p \supset q

If so, then the contrapositive of that would be \sim q \supset \ \sim p which is the final answer. 

The tilde sign \sim means "not" so writing \sim q means "not q" which is the complete opposite of q. 
6 0
4 years ago
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