Start by plugging in all your answer choices and see which ones make the solution true
Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
1/2 x 3/4
1 x 3 / 2 x 4
= 3/8
8 quarters = (8 x .25) = $2.00
5 dimes = (5 x .10) = $.50
$2.00 + $.50 = $2.50
8 + 5 = 13
Answer:
16
Step-by-step explanation:
The differnce of 28 and 12 is 16 because, 28-12=16 and 16+12=28
