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Lisa [10]
3 years ago
9

General douglas MacArthur, one of the leading generals in World War II was born in 1880 and died in 1964 how old was he when he

died? What fractional part of a century did he live
Mathematics
1 answer:
malfutka [58]3 years ago
4 0

Answer: he was 84 years old when he died and the fractional part of a century that he live is 21/25

Step-by-step explanation:

General Douglas MacArthur, one of the leading generals in World War II was born in 1880. He died in 1964. The number of years that he lived would be the year he died - the yea he was born. Therefore,

His age when he died

= 1964 - 1880 = 84 years.

The number of years in a century is 100. Therefore, the fractional part of a century that he lived would be

84/100 = 21/25

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AlekseyPX

Answer:

2,160

Step-by-step explanation:

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3 years ago
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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are
nikitadnepr [17]

Answer:

Area(A)=Area(C)= 9 in^{2}

Area(B)=13.2 in^{2}

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)=\frac{b*h}{2}=\frac{6*3}{2}=9 in^{2}

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

h=[tex]6*cos(30)=5.20in   The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6=31.2 in^{2}

Area(B)=Area(rhomboid)-Area(A)-Area(C)=31.2 in^{2}-9 in^{2}-9 in^{2}=13.2 in^{2}

3 0
3 years ago
PLEASE HELP ME
balandron [24]

Answer:

  • The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is <u>translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis</u>.

Explanation:

By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.

You can check that analitically

Departing from the triangle: XYZ

  • <u>Translation 5 units to the left</u>: (x,y) → (x - 5, y)

  • Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)
  • Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)
  • Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)

  • <u>Translation 1 unit down</u>: (x,y) → (x, y-1)

  • (-11,2) → (-11, 2 - 1) = (-11, 1)
  • (-9,7) → (-9, 7 - 1) = (-9, 6)
  • (-7, 2) → (-7, 2 - 1) = (-7, 1)

  • <u>Reflextion accross the x-axis</u>: (x,y) → (x, -y)

  • (-11, 1) → (-11, -1), which are the coordinates of vertex X"
  • (-9, 6) → (-9, -6), which are the coordinates of vertex Y""
  • (-7, 1) → (-7, -1), which are the coordinates of vertex Z"

Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

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3 years ago
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Nikitich [7]

Answer:

36 yards

Step-by-step explanation:

The triangle is a 3-4-5 right triangle with a scaling factor of 12. No complicated Pythagorean theorem has to be used in this case.

60/12 = 5

48/12 = 4

3 is the only base number remaining.

3(12) =36

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3 years ago
Algebra 2 DCA, I have between two answers which are x and 1, pls help lol
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Answer:

1/x

Step-by-step explanation:

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