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2 years ago

Try it, let's see can u do or not

Mathematics

2 answers:

Firlakuza [10]2 years ago

8 0

Answer:

Step-by-step explanation:

Mashutka [201]2 years ago

6 0

Answer:

EC=2, AD=2.4

Step-by-step explanation:

Objectives: Similar Triangles. We need to establish the scale factor of the similar triangles, and use that factor to find the missing side length.

The corresponding similar side of the left triangle is AD and AB. AB measure is 4.5 and AD measure is 1.5 so this means that AB is 3 times as long as AD. This also means that for the other sides of the left triangle as well.

AC is 3 times as long as AE
BC is 3 times as long as DE

Using this information and what given in the diagram, AC measure is 3 but we need to find EC measure. We can use the addition postulate to find EC.

AE+EC=AC
1+EC=3
EC=2

The same can be done for the triangle on the right. AC is 3 times longer than AE, so this means that AB is 3 times longer than AB using that knowledge, AD measure is 2.4

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3 years ago

What number am i thinking of? a. 21 b. 9 c. 69 d. 7

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3 years ago

Randy said that the number 0.03 has a value 10 times greater than 0.003 is he correct.

pishuonlain [190]

Yes, he is correct. 0.003 * 10 = 0.03

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3 years ago

Pablo has completed 44 deliveries so far this week. He needs to make 55 deliveries for the week. What

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

step one:

completed delivery = 44

total delivery to be made= 55

Step two

Required is the percentage completed

the formula is

=completed/total*100

=44/55*100

=0.8*100

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Hence Pablo has completed 80% of the deliveries so far

3 0

2 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago