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4 years ago

BRAINLIEST ASAPPPPPPPPP

Mathematics

1 answer:

Natali [406]4 years ago

5 0

The answer is C. The IQR is the best measurement of spread for games and movies
hoped this helped

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Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:

agasfer [191]

Answer:12533

Step-by-step explanation:

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3 years ago

Solve by factoring. x² - 121 = 0

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The first one is 11 and -11 because when you square them they both get 121
The second one is -7 and -1

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3 years ago

Shelley designed the patio below, in which one side of the patio is a wall of the house. The length of each side of a square on

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3 years ago

Read 2 more answers

A student selected from a class will be either a boy or a girl. if the probability that a boy will be selected is 0.3, what is t

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The probability that a girl will be selected from the class is 0.7

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3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

3 years ago