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Find the measure of each angle.

tester [92]

Answer:

it looks like all of them should be 90 if I am not incorrect

Step-by-step explanation:

4 0

3 years ago

Sam and Liam raced each other up and then down the hill. Sam's average speed up the hill was 1 mph, and his average speed down w

Furkat [3]

Answer:

Sam's time was 1 hour and 6.66 minutes (or 1 and 1/9 hours)

Liam's time was was 1 hour

So in conclusion, Liam was faster

Step-by-step explanation:

We got Sam's time by 1/1 because Sam was walking 1 mph and the length to reach the top of the hill is 1 mile. So it would take Sam 1 hour to walk 1 mile. Walking down the hill Sam's speed was 9 mph. So the equation would be 1/9. So you would get 1/9. 1/9 of 60 is 6.66 repeating.

For Liam it is pretty simple. Since he is going up the hill at 2 mph and the length of the bottom of the hill to the top is 1 mile, it would be 30 minutes. Repeat this for the top to the bottom and in total it would be 1 hour.

Hope this helps

3 0

3 years ago

Need help on this problem

faust18 [17]

Using an exponential function, it is found that:

For Country A, the doubling time is of 43 years.

For Country B, the growth rate is of 1.9% per year.

<h3>What is the exponential function for population growth?</h3>

The exponential function for population growth is given as follows:

$P(t) = P(0)e^{kt}$

In which:

P(t) is the population after t years.

P(0) is the initial population.

k is the exponential growth rate, as a decimal.

t is the time in years.

For Country A, we have that k = 0.016. The doubling time is t for which P(t) = 2P(0), hence:

$P(t) = P(0)e^{kt}$

$2P(0) = P(0)e^{0.016t}$

$e^{0.016t} = 2$

$\ln{e^{0.016t}} = \ln{2}$

$0.016t = \ln{2}$

$t = \frac{\ln{2}}{0.016}$

t = 43 years.

For Country B, P(36) = 2P(0), hence we have to solve for k to find the growth rate.

$P(t) = P(0)e^{kt}$

$2P(0) = P(0)e^{36k}$

$e^{36k} = 2$

$\ln{e^{36k}} = \ln{2}$

$36k = \ln{2}$

$k = \frac{\ln{2}}{36}$

k = 0.019.

For Country B, the growth rate is of 1.9% per year.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

3 0

2 years ago

A small rock falling from the top of a 124-ft-tall building with an initial downward velocity of -30ft/sec is modeled by the equ

Mandarinka [93]

You need to solve this for h(t)=0

-16t^2-30t+124=0

This has two solutions, one is negative that does not make sense as time cannot be negative.
The positive solution is t=2

So the interval where it is in the air is [0;2)

5 0

3 years ago

Read 2 more answers

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro

Mrac [35]

Answer:

The equation of the displacement $d$ as a function of time $t$ is :

$d(t)=8sin(\pi t+\pi )$

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple $sin$ or $cos$ terms.

Thus,

$d(t) = Asin(wt+c)$

is the general form of displacement of a SHM.

where,

$d(t)$ is the displacement with respect to the mean position at any time $t$
$A$ is amplitude
$w$ is the natural frequency of oscillation ( $rads^{-1}$ )
$c$ is the phase angle which indicates the initial position of the object in SHM ( $rad$ )