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Dmitry_Shevchenko [17]
3 years ago
5

What is the amount saved on pants that were regularly $49.00 with a 6% sales tax?

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

What is the amount saved on pants that were regularly $49.00 with a 6% sales tax?

Step-by-step explanation:

$51.94          If correct thank and give me a good rating hope this helped!

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Step-by-step explanation:

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Need help right now asap??!?!?!??!?!??!
abruzzese [7]

A) The person that has a greater probability of selecting a quadrilateral is Robert.

B) The person that has a greater probability of selecting a polygon is; Robert.

C) The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

<h3>How to Identify Polygons?</h3>

Sandy has; Square, Rhombus, Equilateral Triangle, Regular Hexagon

Robert has Scalene Triangle, Kite, Right Isosceles Triangle, Isosceles Trapezoid, Quadrilateral.

A) Sandy's probability of selecting a quadrilateral = 2/4 = 0.5

Robert's probability of selecting a quadrilateral = 3/5 = 0.6

The person that has a greater probability of selecting a quadrilateral is Robert

B) The person that has a greater probability of selecting a polygon is; Robert because he has more.

C) Probability of Sandy selecting a polygon with at least 2 sides parallel is; 3/4 = 0.75

The Probability of Robert selecting a polygon with at least 2 sides parallel is; 2/5 = 0.4

The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

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6 0
2 years ago
What is 14/52 as a decimal
Kisachek [45]

Answer:

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Step-by-step explanation:

14/52 = 0.2692307692

7 0
3 years ago
Which expression is equivalent to
lutik1710 [3]

Answer:

\frac{\sqrt[4]{3x^2} }{2y}

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use  \frac{a^x}{a^y}=a^{x-y}

Thus, we have:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}

We know 4th root can be written as "to the power 1/4th". Then we can use the property  (ab)^{x}=a^x b^x

<em>So we have:</em>

<em>\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}</em>

<em />

<em>Option D is right.</em>

8 0
3 years ago
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