Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
Answer: The histogram is skewered to the right (right-skewered)
Step-by-step explanation:
The peak veers to the left and the tail is towards the right.
What ?
Step by step step by step equations
1(6x-9)=(4x-6)
One solution was found :
x = 3/2 = 1.500
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
1*(6*x-9)-((4*x-6))=0
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
6x - 9 = 3 • (2x - 3)
Equation at the end of step 2 :
3 • (2x - 3) - (4x - 6) = 0
Step 3 :
Equation at the end of step 3 :
2x - 3 = 0
Step 4 :
Solving a Single Variable Equation :
4.1 Solve : 2x-3 = 0
Add 3 to both sides of the equation :
2x = 3
Divide both sides of the equation by 2:
x = 3/2 = 1.500
One solution was found :
x = 3/2 = 1.500
