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3 years ago

Can anyone give me the answer and how to do it

Mathematics

2 answers:

Gelneren [198K]3 years ago

7 0

Answer:

54 - 10y

Step-by-step explanation:

Distribute each of the 3 parenthesis

= 12y + 24 - 32y + 32 - 10y - 2 ← collect like terms

= 54 - 10y

Liono4ka [1.6K]3 years ago

6 0

Answer = 54 - 10 y

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The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

3 years ago

Plzzzz help!!! quick one

ludmilkaskok [199]

D= 65 degrees.

Because straight line adds up to 180
So 180-115= 65

5 0

3 years ago

39/28 express as a mixed number

xeze [42]

We can do this easily. Since we know that the numerator is more than the denominator, we need to know by how much.

39-28=11; It's only 11 more, which means 11/28 would be the fraction and the whole number is 1.

39/28= 1 11/28

5 0

3 years ago

What number would go in the blank? (3 • 5) • 2 = 3 • (__ • 2) 10 5 2

tester [92]

Answer:

Step-by-step explanation:

It's the one that's missing.

Hope I helped!

Please mark Brainliest!

7 0

2 years ago

Read 2 more answers

A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during

forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

12 properties

This means that $n = 12$

She feels that there is a 50% chance of selling any one property during a week.

This means that $p = 0.5$

Compute the probability of selling no more than 6 properties in one week.

This is:

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127$

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

6 0

2 years ago