You can write these scenarios into equations:
y = distance (in miles)
x = the number of hours [you could put h instead of x, doesn't matter the variable]
Nolan
2x + 4 = y [rides 2 miles per hour(x), and had already gone 4 miles/is 4 miles in]
Hugo
3x = y [rides 3 miles per hour(x), and just started riding]
You can set these two equations equal to each other to find out when they meet: [this will first find how long it will take for them to meet]
2x + 4 = 3x You need to isolate/get x by itself, subtract 2x on both sides
2x - 2x + 4 = 3x - 2x
4 = x Now that you found x, you can use this to find y, you can use either equation to plug in 4 for x
3x = y
3(4) = y
12 = y
2x + 4 = y
2(4) + 4 = y
12 = y
x = 4 hours
y = 12 miles
9514 1404 393
Answer:
x = 10°; angles are 50°, 46°, 84° (CW from left)
Step-by-step explanation:
The sum of the three angles is 180°, so ...
(6x +10°) +(4x +6°) +(7x +14°) = 180°
17x +10° = 180°
17x = 170°
x = 10°
__
Then the angles are ...
6x -10° = 6·10° -10° = 50°
4x +6° - 4·10° +6° = 46°
7x +14° = 7·10° +14° = 84°
Answer:
x = √(28), or x = 5.292
Step-by-step explanation:
First you distribute the square to the values inside of the parentheses. so it ends up looking like this
5(x^2 - 25) - 9 = 6
add 9 to both sides
so its 5(x^2 - 25) = 15
Then distribute the multiplication of 5 to the contents within the parentheses
so it would be 5x^2 - 125 = 15
add 125 to both sides
you get 5x^2 = 140
divide by 5 on both sides
you get x^2=28
then, take the square root of both sides to reverse the square
√(x^2)=√(28)
and in the end you get x=5.292
but √(28) will probably be fine if your teacher doesn't want u to solve for that kind of stuff.
Answer: Transitive Postulate of Inequality (last option)
Explanation:
Let's say we have a vacation where we go from City A, to City B, then to City C. We can use the notation 
. If all we cared about was the first and last cities, then we basically say 
taking a shortcut so to speak.
This analogy is useful to describe the transitive property.
The equality version is where if we had a = b and b = c, then a = c.
The inequality version is where if we had a < b and b < c, then a < c. In this case, c = 2.
In a sense, its like linking together metal chains. A leads to B which leads to C. So we can just jump from A to C.
It might help to draw out a number line and pick values for a and b like a = 0 and b = 1. That way you can see how a < b, b < c and a < c all tie together.
