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3 years ago

Please help a homie out

Mathematics

2 answers:

Helga [31]3 years ago

7 0

Answer:

Option 3: Angle TUV = angle VUW

Step-by-step explanation:

lidiya [134]3 years ago

5 0

Answer:

TUW=VUW

Step-by-step explanation:

You might be interested in

1) Find an equation of the tangent line at each given point on the curve.x = t2 − 4, y = t2 − 2tat (0, 0)at (−3, −1)at (−3, 3)2)

Anastasy [175]

Answer:

1) at ( 0,0) : y = x/2. at(-3-1) : y = -1. at(-3,3) : y = 2x +9

2) DNE ( does not exist )

Step-by-step explanation:

The general equation of tangent line

y - y1 = m( x - x1 )

attached below is the detailed solution on how i derived the answers above

8 0

4 years ago

What is an equation of the line that passes through the point

Mnenie [13.5K]

Answer: y=3/2x+7

Step-by-step explanation:

To find the equation of the line that passes through the given point, let's first convert the given equation to slope-intercept form.

3x-2y=2 [subtract both sides by 3x]

-2y=-3x+2 [divide both sides by -2]

y=3/2x-1

Now that we have the equation in slope-intercept form, we know that the slope must stay the same because parallel lines NEVER touch. All we have to do is plug in the given point to find the y-intercept.

-2=3/2(-6)+b [multiply]

-2=-9+b [add both sides by 9]

b=7

Now, we know that the parallel equation is y=3/2x+7.

4 0

3 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

2 years ago

Mr Thompson, Please help!

BARSIC [14]

Problem 1

<h3>Answer: Choice C) x^2-4 </h3>

Explanation:

Use the difference of squares rule here.

That rule says (a-b)(a+b) = a^2-b^2

In this case, a = x and b = 2.

===========================================================

Problem 2

<h3>Answer: Choice B) 2x^2+7x+5</h3>

Work Shown:

(2x+5)(x+1)

y(x+1) ..... let y = 2x+5

xy+y

x(y) + 1(y)

x(2x+5) + 1(2x+5) ... plug in y = 2x+5

2x^2+5x+2x+5

2x^2+7x+5

===========================================================

Problem 3

<h3>Answer: Choice A) -x^2-5x+7</h3>

Explanation:

The standard form of a quadratic is ax^2+bx+c, where a,b,c are real numbers. In the case of choice A, we have a = -1, b = -5, c = 7.

===========================================================

Problem 4

<h3>Answer: Choice D</h3>

Explanation:

Along the top we have three green rectangles. If each of them are of length x, then we have x+x+x = 3x so far. Then adding on a yellow piece of 1 unit leads to 3x+1 as the total horizontal width across the top.

Similarly, along the left side we have 1 green portion and 2 yellow leading to x+2. So this shows why this diagram represents (3x+1)(x+2)

A rectangle must be formed with the smaller pieces glued together. We cannot have any gaps or overlaps. The reason we're aiming for a rectangle is because the area of a rectangle is length*width. Think of (3x+1) as the length and (x+2) as the width.

8 0

3 years ago

HELP ME PLEASEEEEEEE

elena55 [62]

Answer:

The right answer is : f(-4)=5

6 0

3 years ago