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Kipish [7]
2 years ago
9

For what value of constant c is the function k(x) continuous at x = 0 if k =

Mathematics
1 answer:
nlexa [21]2 years ago
5 0

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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Answer:

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Answer:

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Step-by-step explanation:

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How do you solve recursive formulas
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The number of horses occupying stalls at the county fairgrounds can be modeled by the following function, where x represents the
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Answer:  
_______________________________________________________
The rewritten equation is: 
 

       " - 3x² + 30 + 225 = 0 " ; 

which is ultimately simplified to:

        " x² − 10 − 75  = 0 " .
___________________________________________________
The number of days is:  "15 days" . 
___________________________________________________<span>

Explanation:
______________________________________________
Given:

    h(x) = - 3x</span>² <span>+ 30 + 225  ;  

Rewrite as:  "  </span>- 3x² + 30 + 225 = 0 " ; 
__________________________________________________________
Multiply EACH SIDE of the equation by "-1" ; to get rid of the "-3" ; 

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to get:  " 3x² − 30 <span>− 225 = 0" ; 

Divide EACH SIDE of the equation by "3" ; to simplify; since:

"3", "30", and "225" are divisible by "3" ; 

{</span>3x² − 30 − 225} / 3 = 0 / 3 ; 

 to get: 
______________________________________
 " x² − 10 − 75  = 0 " ; 
 
______________________________________
 Let us factor:

-15 + 5 = -10 ; 

-15 * 5 = -75 ; 
_______________________________________
Rewrite as:

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x = 15;  and x = -5 ; 
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The number of days cannot be "negative value";  so we stick with:

"x = 15 days" 
___________________________________________________
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        " x² − 10 − 75  = 0 " .
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___________________________________________________
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