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Amiraneli [1.4K]
3 years ago
11

I need help with finding area whats the area of a 3m an 7m regtangle​

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
6 0

Answer:

Area of rectangle =LXB

L=7m

B=3m

so 7m multiply by 3m gives 21 so the area is 21

crimeas [40]3 years ago
5 0

Answer:

34

Step-by-step explanation:

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When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
3 years ago
Is this statement true 65.023>65.23?
GarryVolchara [31]

Answer:

No

Step-by-step explanation:

the first one would be 65 and 23/1000, while the other one is 65 and 23/100

8 0
3 years ago
Please help, What is the nth term rule of the quadratic sequence below?<br> -7,-6,-3,2,9,18,29
gulaghasi [49]

Answer:

nth term = tn = n� - 2n - 6

if i'm wrong i'm rlly rlly sorry!!

6 0
3 years ago
What is the answer to 2.25×0.5×0.25?
slega [8]
The answer is 0.28125
8 0
3 years ago
In ΔJKL, the measure of ∠L=90°, JL = 80, KJ = 89, and LK = 39. What is the value of the sine of ∠J to the nearest hundredth
emmainna [20.7K]

Given:

In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.

To find:

The value of sine of ∠J.

Solution:

In a right angle triangle,

\sin\theta =\dfrac{Perpendicular}{Hypotenuse}

In triangle JKL,

\sin J =\dfrac{LK}{KJ}

\sin J =\dfrac{39}{89}

\sin J =0.4382

\sin J \approx 0.44

Therefore, the value of sine of ∠J is about 0.44.

5 0
3 years ago
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