Question

In ΔJKL, the measure of ∠L=90°, JL = 80, KJ = 89, and LK = 39. What is the value of the sine of ∠J to the nearest hundredth

Answer 1

Given:

In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.

To find:

The value of sine of ∠J.

Solution:

In a right angle triangle,

$\sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

In triangle JKL,

$\sin J =\dfrac{LK}{KJ}$

$\sin J =\dfrac{39}{89}$

$\sin J =0.4382$

$\sin J \approx 0.44$

Therefore, the value of sine of ∠J is about 0.44.