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dimaraw [331]
3 years ago
9

The digit in which number represents a value of 9 hundredths

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer : 1.29

Reason : Any number in the second decimal place represents a value of 9 hundredths

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Solve for h.<br> A=3h <br> Can anyone help me?
IgorC [24]

Answer:

h = 3/A

Step-by-step explanation:

A = 3h

Divide both sides by 3 to isolate h:

A/3 = 3h/3

Simplify and get

A/3 = h or h = A/3

Hope this helps!

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2 years ago
Mr. Hebert's class has 36 students and Ms. Green's class has 30 students. For a class competition, each class must be divided in
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3 years ago
How would you change 18/7 into a mix number?
RSB [31]

How many times does 18 go into 7? The answer is 2 times since 14/7 = 2 and we'll have 4 left over. We can say that 18/7 = 2 remainder 4. The remainder of 4 is placed over the denominator 7 to indicate we a fractional part.

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3 years ago
Multiply the following complex numbers: (8-3i)(6+5i)
nika2105 [10]

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3 0
4 years ago
Read 2 more answers
Find the area of the regular polygon. Round to the nearest tenth.
mojhsa [17]

Given:

Side length = 12 in

To find:

The area of the regular polygon.

Solution:

Number of sides (n) = 6

Let us find the apothem using formula:

$a=\frac{s}{2 \tan \left(\frac{180^\circ}{n}\right)}

where s is side length and n is number of sides.

$a=\frac{12}{2 \tan \left(\frac{180^\circ}{6}\right)}

$a=\frac{6}{ \tan (30^\circ)}

$a=\frac{6}{ \frac{1}{\sqrt{3} }}

$a=6\sqrt{3}

Area of the regular polygon:

$A=\frac{1}{2}(\text { Perimeter })(\text { apothem })$

$A=\frac{1}{2}(6 \times 12)(6\sqrt{3} )

$A=\frac{1}{2}(72)(6\sqrt{3} )

A=216 \sqrt{3}

A=374.1 in²

The area of the regular polygon is 374.1 in².

4 0
3 years ago
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