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fgiga [73]
3 years ago
13

Can some body help me with this

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

1 is 11

3 is 12

5 is the same answer as 3

Step-by-step explanation:

for #1 the angle is 90 degrees and its asking to find x you can set up the equation by sayin 46+4x=90 you substract 46 by 46 and subtract 90 by 46 then you will get 4x=44 dived 4 on each side and you will get x = 11

for #3 the angle is equal to 180 you set up the eqation by saying 36+12x=180 you subtract 36 by itself and 180 by 36 then you will get 144 now your equation is 12x = 144 now divide 12x by  12 and 144 by 12 and you will get x = 12

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Step-by-step explanation:

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Please help me and explain! :)
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5 0
3 years ago
A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
aleksandrvk [35]

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

n = 1, so \mu = 3.2.

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so n = 2, \mu = 3.2(2) = 6.4

This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

7 0
3 years ago
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