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We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.
Let y be weight of an object on Mars and x be weight of an object on Earth.
We have been given that the weight of an object on Mars is 34 pounds and weight of the same object on Earth is 90 pounds.
Putting the given values in equation we get
Therefore, our equation now becomes
Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,
We have been given that
Putting the given values in our equation we get
Therefore weight of the object on Mars will be 51 pounds.
Answer:
(a) The probability of 7 people passing by the window in the first hour is 0.000034.
(b) The probability of Y = 17 is 0.1144.
(c) The value of E (Y) and V (Y) is 24.
Step-by-step explanation:
Let <em>Y</em> = number of people who passes by Brad's window per hour.
The random variable <em>X</em> follows a Poisson distribution with parameter, <em>λ </em>= 24.
The probability mass function of a Poisson distribution is:
(a)
Compute the value of P (Y = 7) as follows:
Thus, the probability of 7 people passing by the window in the first hour is 0.000034.
(b)
It is provided that 5 people have already passed by the window in the first 30 minutes.
This implies that in the next 30 minutes 12 people will pass.
The average number of people passing Brad's window in 30 minutes is,
Compute the probability of Y = 17 as follows:
P (Y = 17) = P (12 people passing in the nest 30 minutes)
Thus, the probability of Y = 17 is 0.1144.
(c)
The expected value and variance of a Poisson distribution are same as λ.
So,
E (Y) = 24
V (Y) = 24
Thus, the value of E (Y) and V (Y) is 24.