Answer:
y = 3/2x + 5/2
Step-by-step explanation:
new F=(-7-4,-8-6)= (-11,-14)
new G= (-6-4,-3-6) = (-10,-9)
new H= (5-4,6-6) = (1,0)
Answer:
t = ln(0.5)/-r
Step-by-step explanation:
The decay rate parameter is missing. I will assume a value of 4% per day.
The exponential decay is modeled by the following equation:
A = A0*e^(-r*t)
where A is the mass after t time (in days), A0 is the initial mass and r is the rate (as a decimal).
At half-life A = A0/2, then:
A0/2 = A0*e^(-0.04*t)
0.5 = e^(-0.04*t)
ln(0.5) = -0.04*t
t = ln(0.5)/-0.04
t = 17.33 days
In general the half-life time is:
t = ln(0.5)/-r
3
1
390
x 42
-------
1282
1564
----------------
the answer would be 16380
Hope this helped :)
Its two squares, so you need to start by finding the perfect roots that go into 117. If you need more help after that just comment :)