What is the percent of change from 28 to 70

Solve the system of equations. 2x-6y=8 x-3y=9 Plz help I’m superrr confused

snow_lady [41]

Answer:

There is no solution to this system of equations. The lines do not intersect.

Step-by-step explanation:

Step 1 : See if either x or y can be eliminated.

2x-6y=8

2(x-3y=9)

2x - 6y = 8

2x - 6y = 18

There is no solution to this system of equations as they don't intersect. Notice how we can't cancel out the x or y without canceling the other unknown variable?

Proof : Rearranging the equations above into y = mx + b form, we get

Equation 1 : y = 1/3x - 4/3

Equation 2 : y = 1/3x - 3

A system of equations has no solution when the slopes are the same and both equations have different y intercepts.

5 0

3 years ago

Fran painted 1/2 of the fence around her house.What are two other ways to name 1/2

saveliy_v [14]

6/12 or 4/8 is a possible answer

4 0

3 years ago

Tamu ran 30 minutes and burned 170 calories. PART A: Which equations can be used to find the average number of calories, c, burn

Lena [83]

Answer:

170 divided by 30 or calories divided by minutes

Step-by-step explanation:

the answer could be either but they both mean the same thing just in different words

8 0

3 years ago

annual salary is 48,000 and she earns 4% commission on all sales they make if they want to make a total of 6,000 this month how

AlekseyPX

Subtract 48,000 from 6,000 divide it by 4=10500.

7 0

3 years ago

Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but

grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

$\frac{8km}{55min}=.145\frac{km}{min}$ and we can use that in a d = rt table:

d = r * t

Nina .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

d = r * t

Nina 6 = .145

Jo 6 =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

d = r * t

Nina 6 = .145 * t + 3

Jo 6 = r * t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0

3 years ago