Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.
Let AD=x, Since given AB=3
AD+DB=3
x+DB = 3
DB = 3-x
Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem



Since given AD=BC,let us plugin BC=x in above step.


6x=11
x=
Now we know AD=x=
and given CD=√2.
Let us apply Pythagoras theorem for ΔACD



= 2.315cm
Answer:
4 1/2
Step-by-step explanation:
Apply the fractions formula for division, to
3/4÷1/6
and solve
3/6x4/1
=18/4
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(18,4) = 2
18/24÷2/2=9/2
Convert to a mixed number using
long division for 9 ÷ 2 = 4R1, so
9/2=4 1/2
Therefore:
3/4÷1/6=4 1/2
Given that
, we have
, so that

Take the derivative and find the critical points of
:

Take the second derivative and evaluate it at the critical point:

Since
is positive for all
, the critical point is a minimum.
At the critical point, we get the minimum value
.
Answer:
-30
Step-by-step explanation:
To find slope, subtract two y's and then subtract the x's in the same order.
<u>12-(-18)</u>=<u>30</u>=-30
11-12 -1
You could also switch the order like this...
<u>-18-12</u>=<u>-30</u>=-30
12-11 1
As you can see, both of the ways of solving for slope resulted in -30.
Hope this helps!! Have a great day :3