Answer:
A 2√2(cos 7π/4 + i sin 7π/4)
Step-by-step explanation:
A. 2√2(cos 7π/4 + i sin 7π/4)
2 sqrt(2) ( sqrt(2)/2 - sqrt(2)/2 i)
Distribute
2-2i
This is in the fourth quadrant
B. 2√2(cos 150° + i sin 150°)
2 sqrt(2) (-sqrt(3)/2 +1/2i)
-sqrt(6) +sqrt(2) i
This is in the third quadrant (NO)
C. 2(cos 7π/4 + i sin 7π/4)
2( ( sqrt(2)/2 - sqrt(2)/2 i))
sqrt(2) - sqrt(2) i
This is the fourth quadrant
D. 2(cos 90° + i sin 90°)
2(0+i)
2i
This is on the positive y axis NO
Now we need to decide between the two in the fourth quadrant.
The point has an x coordinate of 2 and a y coordinate of -2
This aligns with point A
A ) ( x - 3 )( x + 1 ) [ not perfect ]
B ) ( x + 5 - √5 )( x + 5 + √5 ) [ n p ]
C ) ( x + 2 + 2√2 )( x + 2 - 2√2 ) [n p ]
D ) ( x - 6 )( x - 6 ) = ( x - 6 )^2 [ perfect ]
Thus the correct answer is option D .
You would do three square in length and 31 in width
-x - y = -5
y = x + 1
-x -(x + 1) = -5
-x - x - 1 = -5
-2x = -5 + 1
-2x = -4
x = -4/-2
x = 2
y = x + 1
y = 2 + 1
y = 3
solution is : (2,3)
