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3 years ago

This figure is made up of two rectangular prisms. What is the volume of the figure?

Mathematics

2 answers:

kow [346]3 years ago

8 0

Answer:

do you

Step-by-step explanation:

give options???I like your pfp btw

ladessa [460]3 years ago

3 0

Answer:

10x3=30 6x12x19=1368 1368+30=1398

Step-by-step explanation:

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-2x-y=-9<br> 5x-2y=18<br> substitution

KIM [24]

$-2x-y=-9 \\
5x-2y=18 \\ \\
\hbox{solve the first equation for y:} \\
-2x-y=-9 \ \ \ |+2x \\
-y=-9+2x \ \ \ |\times (-1) \\
y=9-2x \\ \\
\hbox{substitute 9-2x for y in the second equation:} \\
5x-2(9-2x)=18 \\
5x-18+4x=18 \\
9x-18=18 \ \ \ |\div 9 \\
x-2=2 \ \ \ |+2 \\
x=4 \\ \\
y=9-2x=9-2 \times 4=9-8=1 \\ \\
\boxed{(x,y)=(4,1)}$

6 0

3 years ago

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Draw a diagram using positive an negative tiles for this equation:<br> -5-(-7)=2

Wewaii [24]

Sadly there is no way to graph properly on this website.

5 0

3 years ago

John got 24 out of 25 total questions correct on his test. What percent did he score on his test?

mamaluj [8]

Answer:

24 out of 25 is equal to 96%

96% = A

Step-by-step explanation:

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3 years ago

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Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

What is the answer 4d+12e=

Phantasy [73]

Answer:

d = -3e

Step-by-step explanation:

hope this helps

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3 years ago