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Fiesta28 [93]
3 years ago
11

If the sum of a number and 4 are doubled the result is two less than the number what's the number

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0
The number is -2

-2 + 4 = 2

2 is 2 less than 4
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Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and
Monica [59]

Step-by-step explanation:

We have got the lines :

y=ax+b\\y=cx+d

Both lines intercept the x-axis in the point :

I = (i_{1} ,i_{2})

In all point from x-axis the y-component is equal to 0.

I=(i_{1},o)

We replace the I point in the lines equations:

0=a(i_{1})+b \\0=c(i_{1})+d

From the first equation :

0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}

From the second equation :

0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}

Then i_{1}=i_{1}

Finally :

\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0
3 years ago
pleaseee help context is down below $3 is the entrance fee while $.50 is for each game played that's enough evidence to solve C(
BabaBlast [244]
C= Cost
g= # of times games played

C = 0.50g + 3

C(0) = 0.50(0) + 3
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5 0
2 years ago
Read 2 more answers
Fine the sum of the series
lapo4ka [179]

Answer:

6825

Step-by-step explanation:

From the equation, the series is a geometric series, such that

a = 5

r = 4

n = 6

sum of a geometric series is a(r^n - 1)/(r - 1)

therefore,

sum of the series is 5 x (4^6 - 1) / (4 - 1)

= 5 x (4096 - 1) / 3

= 5 x 4095 / 3

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6 0
3 years ago
When four times a number is decreased by 9, the result is 19. What is the number?
Novay_Z [31]

Answer:

7

Step-by-step explanation:

Working backwards:

19 + 9 = 28

28/ 4 = 7

Checking work:

7 x 4 = 28

28 - 9 = 19

8 0
2 years ago
Read 2 more answers
In Which Quadrant is this true
34kurt

Given:

\sin \theta

\tan \theta

To find:

The quadrant in which \theta lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only \sin\theta and \csc\theta are positive.

In Quadrant III, only \tan\theta and \cot\theta are positive.

In Quadrant IV, only \cos\theta and \sec\theta are positive.

We have,

\sin \theta

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Here, \sin\theta is negative and \tan\theta is also negative. It is possible, if \theta lies in the Quadrant IV.

Therefore, the correct option is D.

5 0
2 years ago
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