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sergij07 [2.7K]
3 years ago
13

?/1 A box contains 5 red marbles and 7 green marbles. Find the probability of drawing a green marble and not returning it to the

box and then drawing a red marble?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer: 35/132

Step-by-step explanation:

probability of drawing green marble: 7/12

since the green marble drawn won't be returned to the box, the new total amount of marbles in the box is 11.

probability of red marble: 5/11

then multiply the 7/12 and 5/11 together:

35/132 which is abut 26.5%

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Ab + c = d solve for B
Zepler [3.9K]

Answer:

b = (d-c)/a

Step-by-step explanation:

ab + c = d

We want to solve for b, so we need to get b alone

Subtract c from each side

ab+c-c = d-c

ab = (d-c)

Divide each side by a

ab/a = (d-c)/a

b = (d-c)/a

7 0
3 years ago
Read 2 more answers
Formula for finding the line of symmetry of a quadratic function?
padilas [110]
It is the line of symmetry of a parabola and divides a parabola into two equal halves that are reflections of each other about the line of symmetry. It intersects a parabola at its vertex. It is a vertical line with the equation of x = -b/2a.
6 0
3 years ago
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Let the abbreviation PSLT stand for the percent of the gross family income that goes into paying state and local taxes. Suppose
gavmur [86]

Answer:

Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

Step-by-step explanation:

We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.

If sigma equals 2.0, we have to find that how many families should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5.

Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.

<u></u>

<u>SO, Margin of error formula is given by;</u>

       Margin of error =  Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }

where, \alpha = significance level = 10%

            \sigma = standard deviation = 2.0

            n = number of families

Now, in the z table the critical value of x at 5% ( \frac{0.10}{2} = 0.05 ) level of significance is 1.645.

SO,        Margin of error =  Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }

                          0.5   =  1.645 \times \frac{2}{\sqrt{n} }

                         \sqrt{n} =\frac{2\times 1.645 }{0.5}

                         \sqrt{n} =6.58

                           n  =  6.58^{2}

                               = 43.3 ≈ 43

Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

4 0
3 years ago
Parallel, perpendicular or neither
sergejj [24]

Answer:

Step-by-step explanation:

x=3 and x=-4 are parallel, vertical lines

:::::

x-y = 3, slope = 1

2x-2y = 10, slope = 1

Parallel lines

3 0
3 years ago
Which statement correctly compares the spreads of the distributions?
swat32

Answer:

b. the ranges of penguin heights are the same.

Step-by-step explanation:

Hello!

Statements:

Which statement correctly compares the spreads of the distributions?

a. the mode of penguin heights at county side zoo is greater than  the mode at city view zoo.

b. the ranges of penguin heights are the same.

c. the range of penguin heights is greater at city view zoo than at  county side zoo.

d. the range of penguin heights is greater at county side zoo than at  city view zoo.

The mode and mean are measurements of central tendency, these indicate the position of a data set but don't show any information concerning the distribution of said data.

The range on the other had is a measurement of variance, it shows the difference between the maximum and minimum values of the data set and indicates its total dispersion.

City view Zoo R= 44-37= 7 cm

County side Zoo: R= 45-38= 7 cm

Both ranges are the same.

I hope this helps!

7 0
3 years ago
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