The range of frequency is from 0.05 to 0.35 and a couple f the numbers aren't close to the other numbers 0.05 is not close to 0.21 or 0.35
so the outcomes do not appear to be equally likely, because of that a uniform probability model wouldn't be a good model.
The answer is A
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Mutiply 5.8 times 1.6 and you will get 9.28
TABLE A = y=5x
TABLE B = y=-1/3x
