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rosijanka [135]
3 years ago
15

I need major help now it’s an emergency

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

yes because together the first 2 people made 27 then you would add 8 to that

Step-by-step explanation:

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Solve the inequality for u.<br> 24 Simplify your answer as much as possible.
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If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed?
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which of the following sets could be the sides of a right triangle? {2,3, square root 13} {5,5,2 square root 10} {5,12,15}
anastassius [24]

All of these sets meet the requirements of the triangle inequality. The sum of any two numbers in the set is greater than the third one. (You really only need to check that the sum of the smallest two is greater than the largest.)

It can help to resolve the numbers that are only indicated as to value.

√13 ≈ 3.606

2√10 ≈ 6.325

_____

Your comparisons can be ...

2 + 3 = 5 > 3.606 . . . is a triangle

5 + 5 = 10 > 6.325 . . . . . . is a triangle

5 + 12 = 17 > 15 . . . . . . . . is a triangle

8 0
3 years ago
If on the unit circle C , the distance from P (1, 0) to the point T ( 5/13, 12/13 ) is x , determine the coordinates of the poin
Lorico [155]

Answer:

T' (\frac{5}{13},- \frac{12}{13})

Step-by-step explanation:

See the diagram attached.

This is a unit circle having a radius (r) = 1 unit.

So, the length of the circumference of the circle will be 2πr = 2π units.

Now, the point on the circle at a distance of x along the arc from P is T(\frac{5}{13},\frac{12}{13}).

Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' (\frac{5}{13},- \frac{12}{13}), where, T' is the image of point T, when reflected over the x-axis. (Answer)

6 0
3 years ago
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