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3 years ago

Which of the following points would fall on the line produced by the point-slope form equation y - 10 = 3(x - 11) when graphed?

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

(-5,-37)

(-4,-34)

(-3,-31)

(-2,-28)

(-1,-25)

(0,-22)

(1,-19)

(2,-16)

(3,-13)

(4,-10)

(5,-7)

(6,-4)

Step-by-step explanation:

y - 10 = 3(x - 11)

y - 10 = 3x - 33

y = 3x -22

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Simplify the expression ?

melomori [17]

Answer:

The answer is cscx(cscx - 1) ⇒ the second answer

Step-by-step explanation:

∵ csc²x = cot²x + 1

∴ $\frac{cot^{2}x+1-1 }{1+sinx}=\frac{cot^{2}x }{1+sinx}$

Multiply the fraction by its conjugate 1 - sinx (up and down)

∴ $\frac{cot^{2}x }{1+sinx}*\frac{1-sinx}{1-sinx}=\frac{cot^{2}x(1-sinx) }{1-sin^{2}x}$

∵ 1 - sin²x = cox²x

∴ $\frac{cot^{2}x(1-sinx) }{cos^{2}x }$

∵ cot²x = cos²x/sin²x

∴ $\frac{1-sinx}{sin^{x}}=\frac{1}{sin^{2}x}-\frac{sinx}{sin^{2}x}=csc^{2}x-cscx$

Take cscx as a common factor

∴ cscx(cscx - 1)

7 0

3 years ago

Solve 2x+3y=26 and x+4y=24 using elimination

kogti [31]

The answer is (6.4, 4.4).

3 0

3 years ago

Read 2 more answers

The picture is a example of how she did one problem.

Svetradugi [14.3K]

Answer:

8000 after 5 years

Step-by-step explanation: Its been so long sence ive done this of stuff im so sorry if its wrong

7 0

3 years ago

Find the perimeter of the quadrilateral.

levacccp [35]

Question:

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

Answer:

<h3>The perimeter of the quadrilateral is 129 inches</h3>

Solution:

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

$4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches$

The values of the side lengths when x = 2 are

$(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch$

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

4 years ago