g(1)=-1 : We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1)=-1 is false.
g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.
So, g(0) =0 is true.
g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.
So, g(4)=-2 is false.
g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1) =1 is true.
g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.
So, g(-1)=1 is true.
g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.
So, g(4)=2 is false.
Answer:
35 green crayons
Step-by-step explanation:
g is number of green crayons
b is number of blue crayons
g = b + 21
plug in 14 for b:
g = 14 + 21
g = 35
35 green crayons
Answer:
science E-notation: 8.900e-10
Engineering Notation: 890.0x-12
real number: 8.9E-10
-.-
Step-by-step explanation:
The curve has been attached and the answer choices are:
y = 3x² – 2x + 1
y = 3x² – 6x + 3
y = 3x²<span> – 7x + 1
</span>
The attached graph has a vertex in the first quadrant. Therefore, the coordinates of the vertex would be both positive.
Let's start with first equation:
y = 3x² – 2x + 1
using the equation of axis:
x = -b/2a
x = 2/6
x = 1/3
SUbstituting the value of x in the main equation to get the y-coordinate of the vertex.
y = 3(1/3)² – 2(1/3) + 1
y = 3/9 – 2/3 + 1
y = 1/3 – 2/3 + 1
y = (1 - 2 + 3)/3
y = 2/3
Hence, the vertex would be:
(h,k) = (1/3 , 2/3)
Also, the leading coefficient is positive, so the parabola would be concave up.
Thus the final answer choice will be:
y = 3x² – 2x + 1
