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3 years ago

Y=1/3x+11/15 find x if y=6

Mathematics

1 answer:

Svetlanka [38]3 years ago

3 0

Step-by-step explanation:

plug in y

6=1/3x+11/15

multiply both sides by 15 to get rid of the fraction

90 = 5x +11

move terms to make them like terms

-5x =11- 90

-5x = -79

divide both sides by -5

evaluate for x

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Step-by-step explanation:

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3 years ago

Use the identity tan(theta) = sin(theta) / cos(theta) to show that tan(???? + ????) = tan(????)+tan(????) / 1−tan(????) tan(????

VMariaS [17]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof the following indentity:

$tan(x+y) = \frac{tan (x) + tan(y)}{1- tan(x) tan(y)}$

So we need to begin with the definition of tangent, we know that $tan (x) =\frac{sin(x)}{cos(x)}$ and we can do this:

$tan (x+y) = \frac{sin (x+y)}{cos(x+y)}$ (1)

We also have the following identities:

$sin (a+b) = sin (a) cos(b) + sin (b) cos(a)$

$cos(a+b)= cos(a) cos(b) - sin(a) sin(b)$

Now we can apply those identities into equation (1) like this:

$tan (x+y) =\frac{sin (x) cos(y) + sin (y) cos(x)}{cos(x) cos(y) - sin(x) sin(y)}$ (2)

We can divide numerator and denominator from expression (2) by $\frac{1}{cos(x) cos(y)}$ we got this:

$tan (x+y) = \frac{\frac{sin (x) cos(y)}{cos (x) cos(y)} + \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{cos(x) cos(y)}{cos(x) cos(y)} -\frac{sin(x)sin(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan (x+y) = \frac{tan(x) + tan(y)}{1-tan(x) tan(y)}$

And that complete the proof.

8 0

3 years ago

Find x and y pls help

ahrayia [7]

Answer:

x = 14

Step-by-step explanation:

110 + 5x = 180

-110 -110

5x = 70

divide by 5 on both sides

x = 14

to find y add 70 + 40 + missing angle = 2y

missing angle is 70 because 70+40+70 = 180

so 2y = 110

y = 55

3 0

2 years ago

Read 2 more answers