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Setler79 [48]
3 years ago
14

Topic - Solving Linear Inequalities.

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

The minimum balance is 68 liters

Step-by-step explanation:

Let the number of liters of petrol required be x

Given that  One litre of petrol has a mass of 737g, x liters will have a mass

= 0.737x kg

Recall that 1 kg = 1000g

Since the empty fuel tank has a mass of 1050kg

The total mass = 1050 + 0.737x IN kg

For the total mass to exceed 1100kg, then

1050 + 0.737x > 1100

0.737x > 1100 - 1050

0.737x > 50

Divide both sides by 0.737

x > 50/0.737

x > 67.84260516

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Answer:

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Step-by-step explanation:

\text{If}\ a,\ b,\ c,\ d,\ e,\ ...\ \text{is a geometric sequence, then}\ \dfrac{b}{a}=\dfrac{c}{b}=\dfrac{d}{c}=\dfrac{e}{d}=....\\\\\#1\\\\\dfrac{7.5}{10}=0.75\\\dfrac{5.625}{7.5}=0.75\\\dfrac{4.21875}{5.625}=0.75\\\boxed{YES}\\================================\\

\#2\\\\\dfrac{40}{160}=\dfrac{1}{4}\\\dfrac{10}{40}=\dfrac{1}{4}\\\dfrac{2.5}{10}=\dfrac{1}{4}\\\boxed{YES}\\================================\\

\#3\\\\\dfrac{70}{20}=3.5\\\dfrac{245}{70}=3.5\\\dfrac{857.5}{245}=3.5\\\boxed{YES}\\================================\\

\#4\\\\\dfrac{16.5}{13}=\dfrac{165}{130}=\dfrac{33}{26}\\\dfrac{20}{16.5}=\dfrac{200}{165}=\dfrac{40}{33}\neq\dfrac{33}{26}\\\boxed{NO}\\================================\\

\#5\\\\\dfrac{5.5}{5}=1.1\\\dfrac{6.05}{5.5}=1.1\\\dfrac{6.655}{6.05}=1.1\\\boxed{YES}\\================================\\

\#6\\\\\dfrac{17.1}{16}=1.06875\\\dfrac{18.2}{17.1}=1.0643274..\neq1.06875\\\boxed{NO}

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