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zvonat [6]
4 years ago
7

Solve for x 7x-4+4y+8=24+31

Mathematics
1 answer:
Anastasy [175]4 years ago
4 0

Answer:

x = -4y/7 + 51/7

Step-by-step explanation:

First, you add all the numbers without variables and are on the same side.

7x - 4 + 4y + 8 = 55

Then you do the opposite sign (for example the opposite of addition is subtraction) of the two numbers without variables on the left side to add them to the right side(what you do on one side of the equation you must do on the other.

4x - 4 + 4 + 4y + 8 - 8 = 55 + 4 - 8

4x + 4y = 51

Then you get the x by itself by doing the same thing you did with the last step by this time with 4y.  Because this has a variable, you don't add it onto the 51, but add as a different number.

4x + 4y - 4y = 51 - 4y

4x = -4y + 51

Now to isolate the x, you divide 4x by 4.

4x/4 = -4y/7 + 51/7

x = -4y/7 + 51/7

Your answer is x = -4y/7 + 51/7

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T=100+40c

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T is the total cost so everything has to add up to that. 100 is a flat cost, plus 40 dollars a month for however long you stay with that program.

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3 years ago
How to do area of irregular figures
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A = (10 x 12) - (2 x 7)
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answer
106 sq. meters
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4 years ago
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3×6×8.........................
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The answer to your question :

3 x 6 x 8 = 144

Hope this helped :)

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the ratio of two numbers is 4:5 after adding 20 to the smaller number and subtracting 20 from the greater number the ratio becom
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Answer:

The numbers are 120 and 150.

Step-by-step explanation:

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4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Lelechka [254]

Answer:

Step-by-step explanation:

(8x²-18x+10)/(x²+5)(x-3)

express the expression as a partial fraction:

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5

both denominator are equal , so require only work with the nominator

(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

x²(A+b)+x(-3b+c)+5A-3c

(8x²-18x+10)

looking at the equation

A+b=8

-3b+c=-18

5A-3c=10

solve for A,b and c (system of equation)

A=2 , B=6, and C=0

substitute in the value of A, b and c

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)

(8x²-18x+10)/[(x^2+5)(x-3)] =

<h2>2/(x-3)+6x/x²+5</h2>

(4x+2)/[(x²+4)(x-2)]

(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)

(4x+2)=a(x²-2)+(bx+c)(x-2)

follow the same step in the previous answer:

the answer is :

<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>

8 0
3 years ago
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