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3 years ago

Solve for x 7x-4+4y+8=24+31

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

Answer:

x = -4y/7 + 51/7

Step-by-step explanation:

First, you add all the numbers without variables and are on the same side.

7x - 4 + 4y + 8 = 55

Then you do the opposite sign (for example the opposite of addition is subtraction) of the two numbers without variables on the left side to add them to the right side(what you do on one side of the equation you must do on the other.

4x - 4 + 4 + 4y + 8 - 8 = 55 + 4 - 8

4x + 4y = 51

Then you get the x by itself by doing the same thing you did with the last step by this time with 4y. Because this has a variable, you don't add it onto the 51, but add as a different number.

4x + 4y - 4y = 51 - 4y

4x = -4y + 51

Now to isolate the x, you divide 4x by 4.

4x/4 = -4y/7 + 51/7

x = -4y/7 + 51/7

Your answer is x = -4y/7 + 51/7

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Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

Which equation is equivalent to StartRoot x squared + 81 EndRoot = x + 10?

marishachu [46]

The given equation is equivalent to Option D .

The mission option is

A. x+10= x+10

B. x+9 =x² + 20x + 100

C. x² +81 = x² + 100

D. x² + 81 = x² +20x + 100

<h3>What is an Equation ?</h3>

An equation is a mathematical statement formed when two algebraic expression is equated by an equal sign .

An equation is given in the question

$\rm \sqrt{x^2 + 81} = x +10$

$\rm {x^2 + 9^2} = (x +10)^2$

$\rm {x^2 + 81} = x^2 +20x + 100$

Therefore the given equation is equivalent to Option D .

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2 years ago

FUNCTION OR NOT /// ALGEBRA I

guapka [62]

Answer:

First figure: The graph is not a function

Second figure:

Statement 1: It is false

Statement 2: It is false

Statement 3: It is right

Step-by-step explanation:

First graph is not a function.

The domain of it is ⇒ 0 ≤ x < 3 , 3 < x ≤ 6 , 6 ≤ x < 9

From the domain ⇒ x = 6 has two corresponding values of y⇒ 3 and 4

∴ It is not a function because every x must have one and only one

corresponding value of y

Second figure

{(3 , 6) , (4 , 6) , (5 , 7) , (6 , 8) , (7 , 10) , (8 , 10)}

<u>Statement 1</u>: It is false because we use x-value to check function or not.

The relation is a function because every x-value has one corresponding

y-value

<u>Statement 2</u>: It is false because 3 ≤ x ≤ 8 means we will use for x all real numbers from 3 to 8 not only the integers 3 , 4 , 5 , 6, ,7 , 8

The domain of this function is { 3 , 4 , 5 , 6 , 7 , 8 }

<u>Statement 3</u>: It is right because the range is the y-value and all the y-value in the function are 6 , 7 , 8 , 10

5 0

3 years ago