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3 years ago

NEED HELP NOWWWWWWWWWWWWW

Mathematics

2 answers:

telo118 [61]3 years ago

5 0

Answer:

Step-by-step explanation:

Masja [62]3 years ago

4 0

Answer: it is 50

Step-by-step explanation: because the 1st triangle is slightly bigger then the second one so its 50 % :)

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Question attached as screenshot below:Please help meI am following along

Ludmilka [50]

Given

x=0 and x =10 and x1, x2, x3, x4 are the midpoints of five equal intervals

Answer

The 5 equal intervals are 2 , 4 , 6, 8 10

Mid points are 1, 3 , 5 , 7 , 9

Option B is correct

3 0

1 year ago

What is 10 less than 812

Temka [501]

The answer will be 802.

5 0

4 years ago

Read 2 more answers

Lisa bought 32.4 ounces of glue. She used 6.8 ounces to put

olga2289 [7]

Answer:

25.6

Step-by-step explanation:

32.4 - 6.8 = 25.6

5 0

3 years ago

Simplify -4(-9p + -3) +2(-2p + 6)

zalisa [80]

Answer:32p+24

Step-by-step explanation:

-4(-9p + -3) +2(-2p + 6)

36p+12-4p+12

32p+24

Hope it helped you

4 0

3 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

7 0

3 years ago