Answer:
The smallest sample size required to obtain the desired margin of error is 44.
Step-by-step explanation:
I think there was a small typing error, we have that 
is the standard deviation of these weighs.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
Which of these is the smallest approximate sample size required to obtain the desired margin of error?
This sample size is n.
n is found when 
So
Simplifying by 15
Rounding up
The smallest sample size required to obtain the desired margin of error is 44.
Assume you mean 3x^2 when you typed the question.
3x^2+14x+16=0
(3x+8)(x+2)=0
x=-8/3 or -2
(35/100)*42= 14.7 days.
This principle apples to all form conversion that requires finding a percentage of a number.
Using the equation y=9x you can substitute x for the hours. Y=9 times 5 and y=9 times 8. Y=45 and y=72. The range is $45-$72
Addition is the first step in solving the equation. Here is how to solve this problem:
x/3 - 3 = 11
+ 3 + 3
------------------------
x
(3) -------- = 14(3)
3
x = 42
