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3 years ago

Questions in the photo. Please HELP!

Mathematics

2 answers:

Ray Of Light [21]3 years ago

7 0

Answer:

Step-by-step explanation: its a

Ede4ka [16]3 years ago

3 0

Answer:

No,

because every line has to equal 180. (for both of them)

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6/2 (1 + 2) ? What is the answer to this the answer choices are: 1, 6, 9, and 3

timama [110]

Answer:

6/2(1+2)

the 2 will divide 6 or go into 6 ,how many times, 3 times because 2*3=6

next 1+2=3

therefore 3(3) =9

5 0

3 years ago

What is 3.8 repeating as a fraction in simplest form

Olin [163]

$\bf 3.8888888\overline{8}\\\\
-------------------------------\\\\
x=3.8888888\overline{8}\qquad thus\qquad 
\begin{array}{llcll}
10x&=&38.888888\overline{8}\\
&&\downarrow \\
&&35+3.8888888\overline{8}\\
&&\downarrow \\
&&35+x
\end{array}
\\\\\\
10x=35+x\implies 9x=35\implies x=\cfrac{35}{9}$

the idea being, you multiply the "x" by some power of 10 that moves the repeating part to the left of the decimal point and the split it like above.

6 0

3 years ago

Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.

kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = $\frac{38}{60} = 0.634$

Therefore, the probability is given by:

$P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]$

P $(p\leq 0.634) = P[z\leq -1.87188]$

P $(p\leq 0.634) = P[z\leq -1.87] = 0.0298$

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0

2 years ago

Help! If anyone knows thanks

DerKrebs [107]

A:
2t
t is the number of toys

b:
(p+12)/16
p is the price

6 0

3 years ago

Read 2 more answers

Activity

hodyreva [135]

Answer:

The answers to each part are:

Part A.

The quantity of apples is one-third of the quantity of grapes.

Part B.

The quantity of apples is a quarter of the quantity of strawberries.

Part C.

The number of cherries is two-elevenths of the total fruit.

Step-by-step explanation:

To identify the answer in each case, you must remember that all the parts are equal, then:

Part A.

The parts of apples are 1 and the parts grapes are 3, so if you divide the first quantity with the second quantity you obtain:

1 / 3 = 1/3 (one-third)

So, the quantity of apples is one-third of the quantity of grapes or the quantity of apples is three times smaller than the quantity of grapes.

Part B.

The parts of apples are 1 and the parts of strawberries are 4, then you must divide the first quantity with the second quantity:

1 / 4 = 1/4 (a quarter)

In this case, the quantity of apples is a quarter of the quantity of strawberries or the quantity of apples is four times smaller than the quantity of strawberries.

Part C.

First, you must add all the part of fruit:

1 part apple
1 part orange
4 parts strawberry
2 parts cherry
3 parts grape

The total of fruits is 11 parts, taking into account the quantity of cherries is 2, now you can divide the number of cherries with the total parts of fruit:

2 / 11 = 2/11 (two-elevenths)

Now, you can see the number of cherries is two-elevenths of the total fruit.

3 0

3 years ago