well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus
Use y=mx + b, which is slope intercept form
b = y intercept(when x=0)
m = slope
You need to find the y intercept. Use your coordinates and substitute it in the slope intercept equation.
we use (6, -8)
y = mx + b
Then, -8 = -3/2(6) + b
-8 = -9 + b
1 = b
Thus,
y = -3/2x + 1
Answer:
49
Step-by-step explanation:
25b² + 70b + ....
( 5b + 7)² = 5×5b² + 2×5×7b + 7×7 = 25b² + 70b + 49
<span>1/4= y-intercept
</span><span>-1/7= x intercept </span>
