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saw5 [17]
3 years ago
5

Which statements are true?

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:


Step-by-step explanation:i ant see it well try zooming in a little more and i can see


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A wood board 156 centimeters long is cut into three parts. The two longer parts are the same length and are 15 centimeters longe
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The three parts are a -141
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A theater production charges $21 for adult tickets and $15 for student tickets. If the
Zarrin [17]

Answer:

The number of adult tickets sold was 67, and the number of student tickets sold was 35.

Step-by-step explanation:

7 0
2 years ago
85,000lb greater than or less than or equal to 40 t​
pshichka [43]

Answer:

Step-by-step explanation:

Less than, 40 tons in pounds is 80000.

6 0
3 years ago
Read 2 more answers
Evaluate if X = 5 and Y = 10<br> 5 + 7X - 3Y
svp [43]

Answer:

10

Step-by-step explanation:

Plug in 5 for x, and 10 for y in the expression:

5 + 7(5) - 3(10)

Remember to follow PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponent (& Roots)

Multiplication

Division

Addition

Subtraction

First, Multiply:

7 * 5 = 35

-3 * 10 = -30

5 + 35 -  30

Combine like terms:

(5 + 35) - 30

40 - 30 = 10

10 is your answer.

~

5 0
3 years ago
The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
Bad White [126]

Answer:

1. Test statistic t=1.581.

2. The null hypothesis H0 failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

NOTE: if the null hypothesis is µ = 40, there is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40 (test statistic t=3.161).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 41.

Then, the null and alternative hypothesis are:

H_0: \mu=41\\\\H_a:\mu> 41

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-41}{0.633}=\dfrac{1}{0.633}=1.581

The degrees of freedom for this sample size are:

df=n-1=38-1=37

This test is a right-tailed test, with 37 degrees of freedom and t=1.581, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>1.581)=0.061

As the P-value (0.061) is bigger than the significance level (0.025), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

<u><em>For µ = 40:</em></u>

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 40.

Then, the null and alternative hypothesis are:

H_0: \mu=40\\\\H_a:\mu> 40

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-40}{0.633}=\dfrac{2}{0.633}=3.161

The degrees of freedom for this sample size are:

df=n-1=38-1=37

This test is a right-tailed test, with 37 degrees of freedom and t=3.161, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>3.161)=0.002

As the P-value (0.002) is smaller than the significance level (0.025), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40.  

3 0
3 years ago
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