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ratelena [41]
1 year ago
15

Vassil rounded to the nearest half to estimate the product of Five-eighths and StartFraction 8 over 9 EndFraction. How do the es

timated and actual products compare?
(Hint: use 18 for the denominator when comparing.)
The actual product is about StartFraction 1 over 18 EndFraction greater than the estimate.
The actual product is about StartFraction 1 over 18 EndFraction less than the estimate.
The actual product is about StartFraction 1 over 9 EndFraction greater than the estimate.
The actual product is about StartFraction 1 over 9 EndFraction less than the estimate.
Mathematics
1 answer:
Mice21 [21]1 year ago
5 0

The correct answer is option B which is the actual product is about StartFraction 1 over 18 EndFraction less than the estimate.

<h3>What are fractions?</h3>

The fraction is defined as the division of the whole part into an equal number of parts. here we have the following information Vassil rounded to the nearest half to estimate the product of Five-eighths and StartFraction 8 over 9 EndFraction.

E =  \dfrac{5}{8}\times \dfrac{8}{9} = 0.55

Thus the product of the fraction estimated in the nearest half is,

0.5×1= 0.50

Therefore the correct answer is option B which is the actual product is about StartFraction 1 over 18 EndFraction less than the estimate.

To know more about fractions follow

brainly.com/question/78672

#SPJ1

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What is the general term equation, an, for the arithmetic sequence 5, 1, â3, â7, . . . , and what is the 21st term of this seque
Valentin [98]
Hello :

the nth term ( general term  of an arithmetic sequence is :

An =A1+(n-1)d   ....a common difference is : d , A1 : the first terme
A1 = 5    and : d = 1 - 5 = - 4    n = 21
A21 = 5 + (21 -1)(-4)
A21 = 5 - 80 = -75

<span>                                      
</span>

3 0
3 years ago
The test scores of a geometry class are given below. 90, 75, 72, 88, 85 The teacher wants to find the variance for the class pop
ella [17]
The data given as a whole would be called ungrouped data. Now to get the variance, you will need the formula:

s^2=   <u>Σ(x-mean)^2</u>
                   n      

x = raw data
mean = average of all data
n = no. of observations
s^2 = variance

Now we do not have the mean yet, so you have to solve for it. All you need to do is add up all the data and divide it by the number of observations. 

Data: <span>90, 75, 72, 88, 85        n= 5  
</span>Mean=<u>Σx</u>
            n
Mean = <u>90+75+72+88+85 </u>  = <u>410</u> = 82
                        5                        5

The mean is 82. Now we can make a table using this.

The firs column will be your raw data or x, the second column will be your mean and the third will be the difference between the raw data and the mean and the fourth column will be the difference raised to two. 

90-82 = 8
8^2 =64

75-82 = -7
-7^2 =49

72-82 = -10
-10^2=100

88-82=6
6^2 = 12

85-82=3
3^2=9

Now you have your results, you can now tabulate the data:

 x      mean         x-mean        (x-mean)^2     
90       82                8                      64                       
75       82               -7                      49
72       82              -10                    100
88       82                6                       36
85       82                3                       9

Now that you have a table, you will need the sum of (x-mean)^2 because the sigma sign Σ in statistics, means "the sum of."

64+49+100+36+9 = 258

This will be the answer to your question. The value of the numerator of the calculation will be 258.

 
<u>
</u>
6 0
3 years ago
Kelly works two jobs. She usually works at a retail store for 8 hours during the day and is paid $12.90 per hour by the store. I
quester [9]

Answer:

i believe its 12.55

Step-by-step explanation:

if you add both number,  12.90 and 12.20, then divide by 2.

you'll will gain the same result

6 0
2 years ago
What is the answer to this question?
frez [133]

Answer:

Algebra byan hhhaaahha

5 0
2 years ago
Can someone please help me with 10-16 it’s due tomorrow!!! Please
VMariaS [17]
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15)  V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
7 0
3 years ago
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