Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
B. 5(4x+2y)-y
Step-by-step explanation:
Bring the 5 over and multiply
5×4 = 20 + x
=20x (thats the beginning of the expression)
5×2 = 10
10y - y = 9 because the - y is basically telling you to get rid of one of the y values so 10 - 1 = 9y
Answer:
The equation is not a linear function.
Increases but is that what you are asking?
