hope it will help you..........
<em>Here we are required to determine the initial monthly fee charged by the electric company.</em>
The initial fee charged by the electric company is; C = $10
To solve this, we need to evaluate the slope and intercepts of the equation of the straight line graph of the relation.
y = mx + c.
- where m = slope of the relation.
- and c = <em>intercept = the initial fee charged by the electric company</em>.
- y = <em>Monthly charge at each time</em>.
To find the slope;
By substituting m into the equation y = mx + c, alongside a pair of values of usage and monthly charge, we can obtain the intercept, c (i.e the initial fee charged).
Therefore, m = 0.12 , y = 82 and X = 600;
we then have;
Therefore, the initial fee charged by the electric company is; C = $10.
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Whats the question??????????????????????
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
Answer:
i cant see the graph, how do you expect us to awser you
