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Natali [406]
3 years ago
14

Which inequality is NOT true if y = -5?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer:

2y-10>13

Step-by-step explanation:

2(-5)-10=-20 <13 not true

3(-5)+9=-5>-15 true

-24-4(-5)=-4<-3 true

-14+6(-5)=-44<8 true

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y=-1/2x-3

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) Factor 9x² + 6x + 12x + 8.​
hram777 [196]

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(3x+4)(3x+2)

Step-by-step explanation:

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Plz I need help fast
Norma-Jean [14]

Answer:

the answer is 1y>19

Step-by-step explanation:

i didn't study this at school yet

3 0
3 years ago
Please help! Both questions are in the photo. Thank you so much!
tangare [24]

The probability that a 4 shows up is 0.20 and the proportion of 3's rolled is 0.467

<h3>The probability that a 4 shows up</h3>

From the list of numbers, we have:

  • Sides = 5 i.e. numbers 1 to 5
  • n(4) = 1 i.e. sides labelled 4

The probability that a 4 shows up is then calculated as:

P = n(4)/Sides

This gives

P = 1/5

Evaluate

P = 0.2

<h3>The proportion of 3's rolled</h3>

In the list of numbers, we have:

  • Total = 15
  • Number of 3's = 7

The proportion of 3's rolled is then calculated as:

P = Number of 3's/Total

This gives

P = 7/15

Evaluate

P = 0.467

Hence, the proportion of 3's rolled is 0.467

Read more about probability at:

brainly.com/question/25870256

#SPJ1

7 0
2 years ago
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% conf
adelina 88 [10]

Answer:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.1 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

3 0
4 years ago
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