Question

Describe the nature of the roots for the equation 49x2– 28x +4 = 0

Answer 1

Answer:

The roots of the equation is real and repeated

Step-by-step explanation:

Here, we want to describe the nature of the roots of the given quadratic equation

To get the nature of the roots, we find the discriminant of the equation

The discriminant is;

b^2 - 4ac

In this case, b = -28 , a = 49 and c = 4

The discriminant is thus;

-28^2 - 4(49)(4)

= 784 - 784 = 0

Since the discriminant is zero, this means that the quadratic equation has real roots which are the same