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BARSIC [14]
3 years ago
8

The following triangles are similar. State the postulate or theorem that proves they are similar along with the correct scale fa

ctor. The diagram is not to scale.
a. SSS~; 3:4
b. SAS~; 1:3
c. SSS~; 1:3
d. SAS~; 3:4

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0
I would have to say SAS because they give 2 sides and an angle. Also 3:4 because the one side is 3 and add 1 for 4, same for 30 and 40. 
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Garrett and Carter went to the movies last weekend. Together they bought 2 drinks and 2 popcorns. They spent a total of $12.50.
-BARSIC- [3]

The cost of one drink is $2.50 and cost of one popcorn is $3.75

<u><em>Explanation</em></u>

Suppose, the cost of one drink is x dollar and cost of one popcorn is y dollar.

Given that, total cost for 2 drinks and 2 popcorns is $12.50  and  total cost for 6 drinks and 5 popcorns is $33.75

So, the system of equations will be......

2x+2y=12.50 ..................................... (1)\\ \\ 6x+5y= 33.75 ..................................... (2)

Multiplying equation (1) by -3 , we will get.....

-3(2x+2y)=-3(12.50)\\ \\ -6x-6y=-37.50 ..................................... (3)

Now, adding equation (2) and equation (3) , we will get ............

5y-6y=33.75-37.50\\ \\ -y=-3.75\\ \\ y=3.75

Plugging this y=3.75 into equation (1) ......

2x+2(3.75)=12.50\\ \\ 2x+7.50=12.50\\ \\ 2x=12.50-7.50=5\\ \\ x=\frac{5}{2}=2.50

So, the cost of one drink is $2.50 and cost of one popcorn is $3.75


6 0
3 years ago
Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!​
Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

\frac{3}{x + 4}  - \frac{1}{x + 3}  = \frac{x + 9}{(x^2 + 7x + 12)}

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

\frac{3*(x + 4)}{x + 4}  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

3  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x + 3)

3*(x + 3)  - \frac{(x + 4)*(x+3)}{x + 3}  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

3*(x + 3)  - (x + 4)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

(2*x + 5)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x^2 + 7*x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = (x + 9)*(x + 4)*(x+3)

Now we need to solve this:

we will get

2*x^3 + 19*x^2 + 59*x + 60 =  (x^2 + 13*x + 3)*(x + 3)

2*x^3 + 19*x^2 + 59*x + 60 =  x^3 + 16*x^2 + 42*x + 9

Then we get:

2*x^3 + 19*x^2 + 59*x + 60 - (  x^3 + 16*x^2 + 42*x + 9) = 0

x^3 + 3x^2 + 17*x + 51 = 0

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

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3 years ago
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Answer:

4/sin (35)

Step-by-step explanation:

sin(35)=4/AB

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zavuch27 [327]

Answer: 6

Step-by-step explanation:

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3 years ago
A car travels 42 miles for every 2 gallons of gasoline. What is the unit rate?
svetoff [14.1K]

Answer:

21 miles per 1 gallon

Step-by-step explanation:

The unit rate is how many to 1 so, 42 divided by 2 equals 21 so, the answer is given.

PLZ MARK BRAINLIEST!!!

5 0
3 years ago
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