Question

. Center at (-4,-1), radius = 2​

Answer 1

Consider we need to find the equation of the circle.

Given:

The Center at (-4,-1), radius = 2​.

To find:

The equation of the circle.

Solution:

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting h=-4, k=-1 and r=2, we get

$(x-(-4))^2+(y-(-1))^2=(2)^2$

$(x+4)^2+(y+1)^2=4$

Therefore, the equation of the circle is $(x+4)^2+(y+1)^2=4$.