Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest

7 0

3 years ago

I need to know how to solve this

jeyben [28]

The answer is 3 4/5 !!

5 0

3 years ago

Read 2 more answers

Which point is on the circle centered at the origin with a radius of 5 units?

Aleonysh [2.5K]

Answer:

(2,√21)

Step-by-step explanation:

The circle centered at the origin has equation:

${x}^{2} + {y}^{2} = 25$

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.

${2}^{2} + {y}^{2} = 25 \\ 4 + {y}^{2} = 25 \\ {y}^{2} = 25 - 4 \\ {y}^{2} = 21$

Take square root to get:

$y = \pm \sqrt{21}$

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

3 0

3 years ago

Read 2 more answers