To see this, notice that if you remove 25 and 41 from your sequence, then the average of the remaining terms is still given by the average of the extreme terms 26+40/2=33.

7 0

4 years ago

Find the distance between the complex numbers. z1=9-9i, z2=10-9i

kherson [118]

$\bf z_1=\stackrel{a}{9}\stackrel{b}{-9}i\implies (9~,~-9)\qquad \qquad \qquad z_2=\stackrel{a}{10}\stackrel{b}{-9}i\implies (10~,~-9)\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\$

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 9}} &,&{{ -9}}~) 
% (c,d)
&&(~{{ 10}} &,&{{ -9}}~)
\end{array}\quad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[10-9]^2+[-9-(-9)]^2}\implies d=\sqrt{(10-9)^2+(-9+9)^2}
\\\\\\
d=\sqrt{1^2+0}\implies d=\sqrt{1}\implies d=1$

4 0

3 years ago