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2 years ago

Is 49 the gcf of 42 and 154

Mathematics

1 answer:

Eduardwww [97]2 years ago

6 0

No, 14 is the gcf of 42 and 154.

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Jeremy has $30. He pays $8 to wash his car. His friend pays back $16 that Jeremy had loaned to him. How much money does Jeremy h

GREYUIT [131]

Answer: $38 because 30-8= 22, 22+16=38

3 0

2 years ago

Read 2 more answers

Kevin operates a movie theater that sells about 800 tickets per day for $8 each. Kevin predicts that for each $0.50 increase in

dmitriy555 [2]

Answer:

The function reveals that the maximum earning from ticket sales will be $6480 after 2 ($0.50) price increases

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = -20x² + 80x + 6400 represents the total

earnings from ticket sales and x represents the number of $0.50

price increases

∵ f(x) is a quadratic function

∵ The coefficient of x² is -20

∴ The function has a maximum value

- The vertex of the quadratic function f(x) = ax² + bx + c is (h , k),

where h = -b/2a and k = f(h)

* Lets find the maximum point of f(x)

∵ a = -20 , b = 80

∵ h = -b/2a

∴ h = -(80)/2(-20) = -80/-40 = 2

∵ k = f(h) and h = 2

∴ f(2) = -20(2)² + 80 (2) + 6400

∴ f(2) = -80 + 160 + 6400

∴ f(2) = 6480

∴ k = 6480

* The function reveals that the maximum earning from ticket sales

will be $6480 after 2 ($0.50) price increases

3 0

2 years ago

What is the difference between -7 and 8? 15 -15 1 -1

Lunna [17]

Difference = -

- 7 - (+ 8) = - 7 - 8 = -15

5 0

2 years ago

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Simplify this expression

Juliette [100K]

x^2+2x+1
= x^2 + 1x + 1x + 1
= (x^2+1x) + (1x+1)
= (x+1)(x+1)

3 0

2 years ago

You have 16 different cuts of flowers and plan to use seven of them how many different selections of the seven flowers are possi

alisha [4.7K]

We can have 11440 different selections.

SOLUTION: 

Given, you have 16 different cuts of flowers

And you have planned to use seven out of them.

We have to find how many different selections of the seven flowers are possible. Now, we have to select 7 items out of 16 available items. So we have to use combinations.

Then, 7 out of 16 combination $\rightarrow^{16} \mathrm{c}_{7} \rightarrow \frac{16 !}{(16-7) ! 7 !}$

$\bold{\text{ Since } ^nC_r=\frac{n !}{(r !(n-r) !)}}$

$\begin{array}{l}{\rightarrow \frac{16 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10}{7 \times 6 \times 13 \times 12 \times 11 \times 10}} \\\\ {\rightarrow \frac{57657600}{5040}} \\\\ {\rightarrow 11440}\end{array}$

Hence, we can have 11440 different selections.

6 0

3 years ago