So slope intercpet form
y=mx+b
m=slope
b=y intercpet
slope=5/3
in (x,y) form
x=3
y=5 is one point
subsitute and solve for b
y=mx+b
5=5/3 times 3+b
5=3/3 times 5+b
5=1 times 5+b
5=5+b
subtract 5 from both sides
0=b
equation is
y=5/3x+0 or
y=5/3x
There’s is a 40% chance the next page she turns will be an add.
You can parameterize using spherical coordinates by
with and .
Take the normal vector to to be
(I use to avoid negative signs. The orientation of the normal vector doesn't matter for a scalar surface integral; you could just as easily use .)
Then
and the integral of over is
Answer:
m<ABC=94°
m<BCD=25°
m<ACB=43°
Step-by-step explanation:
To find <mBCD
m<ABD=133°, so m<CBD=133° too.
A triangle is equal to 180°.
22°+133°=155°
80°-155°=25°
To find <mACB
You first need to know triangle ACD measurements.
m<ADC=44° (22°+22°)
Then you take the two 25 and add them.
25°+25°=50°
50°+44°=94°
180°-94°=86°
86°÷2=43°
To find m<ABC
43°+43°=86°
180°-86°=94°