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3 years ago

Can anyone do this please

Mathematics

1 answer:

morpeh [17]3 years ago

8 0

Answer:

I know for the fact that it's the first one but I don't know the other answer

Step-by-step explanation:

An equation of a graph is y=mx+b and the B is the y-intercept which is -2 since the line is on top of -2. mx is the rise/run of -2 which is -3/2

Hope this helps, but I don't which other equation represents the graph.

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HELP ASAP PLS :Find all the missing elements:

Deffense [45]

Answer:

a ≈ 1.59

b ≈ 6.69

Step-by-step explanation:

Law of Sines: $\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Step 1: Find <em>c</em> using Law of Sines

$\frac{6}{sin58} =\frac{c}{sin13}$

$c = sin13(\frac{6}{sin58})$

c = 1.59154

Step 2: Find <em>a</em> using Law of Sines

$\frac{6}{sin58} =\frac{a}{sin109}$

$a = sin109(\frac{6}{sin58} )$

a = 6.68961

3 0

4 years ago

Paul can type 60 words per minute and Jennifer can type 80 words per minutes.How does Paul's typing speed compare to Jennifer's

valina [46]

Paul can type 3/4 as fast as Jennifer. 60/80=6/8=3/4

7 0

3 years ago

-2 < 3x+4 < 31 find x

Eva8 [605]

First rewrite into 2 inequalities,

$-2\lt3x+4$

$3x+4\lt31$

Solve each of the inequalities,

$-2\lt3x+4\implies3x\gt-6\implies x\gt-2$

$3x+4\lt31\implies 3x\lt27\implies x\lt9$

So our x is between -2 and 9 which can be written as,

$-2\lt x\lt9$

or as an interval,

$x\in(-2,9)$

Hope this helps :)

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Cdiv%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title=" \

saul85 [17]

1.5 hopes this helps

8 0

3 years ago

Read 2 more answers

C 17. At high school A, the mean score of 50 students on a science test is 75.

givi [52]

Answer:

Mean score of 90 students = 77.2

Step-by-step explanation:

Mean score of 50 students from school A = 75

Mean score of 40 students from school B = 80

We need to find mean score of the 90 students?

First we will find sum of scores of students from school A

We know that: $Average=\frac{Sum\:of\:Terms}{Number\:of\:terms}$

We have Average = 75, Number of terms = 50, We need to find Sum of terms (scores)

$Average=\frac{Sum\:of\:Terms}{Number\:of\:terms}\\75=\frac{Sum\:of\:Terms}{50}\\Sum\:of\:Terms= 75\times 50\\Sum\:of\:Terms=3750$

So, Sum of scores for School A = 3750

Now, we will find sum of scores of students from school B

We know that: $Average=\frac{Sum\:of\:Terms}{Number\:of\:terms}$

We have Average = 80, Number of terms = 40, We need to find Sum of terms (scores)

$Average=\frac{Sum\:of\:Terms}{Number\:of\:terms}\\80=\frac{Sum\:of\:Terms}{40}\\Sum\:of\:Terms= 80\times 40\\Sum\:of\:Terms=3200$

So, Sum of scores for School B = 3200

Now, We will find mean score of the 90 students?

Mean score of 90 students will be:

$Average=\frac{Sum\:of\:Terms}{Number\:of\:terms}\\Average=\frac{3750+3200}{90}\\Average=\frac{6950}{90}\\Average = 77.2$

So, mean score of 90 students = 77.2

8 0

3 years ago