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My name is Ann [436]

3 years ago

7

The probability of selecting a pink piece of construction paper is 23/60 . The chance of selecting a pink piece of construction

paper is ___________. Answer Choices

2 answers:

andrew-mc [135]3 years ago

7 0

15% is the probability

gregori [183]3 years ago

6 0

15% is the chance..................

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Four times a number is 84 what is the number

Elanso [62]

21 because you can do 84 divided by 21 or you can also do 4 times any number that sounds like it would =84. (Stick with option 1 unless you are super confused)

8 0

2 years ago

Need help on 1 and 2 plzzz help !!!!!

Vesna [10]

Subtract 1 to 13. so you got 12. divide 4 so you can get the S by it self.S=3.

6 0

3 years ago

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What is the sum of the first five terms of the geometric series 2 − 8 + 32 −

MrMuchimi

Answer:

∑ (n = 1 to 5) (2·(-4)^(n - 1))

S5 = 2·((-4)^5 - 1)/((-4) - 1) = 410

5 0

2 years ago

I rlly need help help me out pls

rusak2 [61]

Answer:

San francisco

Step-by-step explanation:

once you divide the distance by time then multiply the answer by the longest amount of time (aka 4)

San francisco = 2556

Minot = 1826

Phoenix = 2252

6 0

2 years ago

Annie writes the numbers 1 through 10 on note cards. She flips the cards over so she cannot see the number and selects three car

Kay [80]

<h2>The probability that Annie has selected the cards numbered 1, 2, and 3 is $(\frac{1}{720} )$ </h2>

Step-by-step explanation:

Here, the total number of cards in the set = 10

The cards are numbered as 1,2,3,4,5,...., 10

P(Any event E) = $\frac{\textrm{Total favorable events}}{\textrm{Total number of events}}$

P(picking a card with number 1) = $\frac{\textrm{Total cards with number 1 on it}}{\textrm{Total cards}} = (\frac{1}{10})$

Now when the first card is picked, the number of cards left = 10 - 1 = 9

P(picking a card with number 2) = $\frac{\textrm{Total cards with number 2 on it}}{\textrm{Total cards}} = (\frac{1}{9})$

Similarly, P(picking a card with number 3) = $\frac{\textrm{Total cards with number 3 on it}}{\textrm{Total cards}} = (\frac{1}{8})$

So, the total probability that she has selected card with number 1, 2 and 3

= $(\frac{1}{10} ) \times (\frac{1}{9} ) \times (\frac{1}{8} ) = (\frac{1}{720} )$

Hence, the probability that she has selected the cards numbered 1, 2, and 3 is $(\frac{1}{720} )$

4 0

3 years ago

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