<img src="https://tex.z-dn.net/?f=x%5E%7B-2%7D%20-4x%5E%7B-1%7D%20-3%3D0" id="TexFormula1" title="x^{-2} -4x^{-1} -3=0" alt="x^{

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Brilliant_brown [7]

3 years ago

-2} -4x^{-1} -3=0" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

crimeas [40]3 years ago

6 0

If you are trying to find the value of X, it’s 0

eimsori [14]3 years ago

6 0

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Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e

Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let $\%R_{A}$ be the quantity of nonzero elements in $R_{A}.$

Let $C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right)$ .

Parity demands that $\%R_{A}$ and $\%R_{B}$ must equal 2 or 4.

Case 1: $\%R_{A}$ =4 and $\%R_B$ =4. There are $\left(\begin{array}{l}3\\ 2\end{array}\right)$ =3 ways to put 2-1's in $R_A$ , so there are 3 ways.

Case 2: $\%R_{A}$ =2 and $\%R_B$ =4. There are 3 ways to position the -1 in $R_A$ , 2 ways to put the remaining -1 in $R_B$ (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of $\%R_{A}=4,\%R_{B}=2$ for a complete of 24 ways.

Case 3: $\%R_A=\%R_B=2$ . There are 3 ways to put the -1 in $R_{A}$ . Now, there are two cases on what happens next.

The 1 in $R_B$ goes directly under the -1 in $R_A$ . There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in $R_C$ and $R_D$ . (Either the 1 comes first in $R_C$ or the 1 comes first in $R_D$ .)
The 1 in $R_B$ doesn't go directly under the -1 in $R_A$ . There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

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3 0

2 years ago

Read 2 more answers

Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

Part A) $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

the answer Part A is

$9-----> A$

Part R) $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

the answer Part R is

$14-----> R$

Part Y) $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

the answer Part Y is

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

the answer Part S is

$23-----> S$

Part O) $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

the answer Part O is

$17-----> O$

Part E) $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

the answer Part E is

$3-----> E$

Part I) $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

the answer Part I is

$20-----> I$

Part D) $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

the answer Part D is

$10-----> D$

Part W) $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

the answer Part W is

$18-----> W$

Part E) $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

the answer Part E is

$7-----> E$

Part T) $0.5(4a+10)=2a+$

Using the distributive property

Part T) $0.5(4a+10)=2a+5$

therefore

the answer Part T is

$1-----> T$

Part R) $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

the answer Part R is

$6-----> R$

Part O) $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

the answer Part O is

$13-----> O$

Part T) $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

the answer Part T is

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

the answer Part W is

$16-----> W$

Part H) $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

the answer Part H is

$2-----> H$

Part E) $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

the answer Part E is

$11-----> E$

Part A) $bu+uv=\ (b+v)$

$bu+uv=u(b+v)$

therefore

the answer Part A is

$5-----> A$

Part F) $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

the answer Part F is

$12-----> F$

Part M) $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

the answer Part M is

$8-----> M$

Part S) $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

the answer Part S is

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

the answer Part T is

$15-----> T$

Part R) $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

the answer Part R is

$19-----> R$

the answer is

they are made for two wrists

4 0

3 years ago

Read 2 more answers

Find the slope of the line y = 1/6x + 3/2

AURORKA [14]

Answer: 1/6

Step-by-step explanation:

Slope is the m in y=mx+b

7 0

3 years ago

Read 2 more answers

What is 5/10 in decimal

Tcecarenko [31]

Well you can either think of actually dividing the fraction or reduce to lowest forms which is 1/2. then from 1/2 you can either divide that or just say it is .5.

4 0

3 years ago

Find the formula for the area A and the perimeter P of the shape shown find the area and perimeter when R is 5 cm find R when A

Ghella [55]

Answer:

1)Area; A = ¼πr²

Perimeter; P = πr/2 + 2r

2)A = 19.63 cm²

P = 17.85 cm

3) r = 8.885 cm

4) r = 14 cm

Step-by-step explanation:

This is a quadrant of a circle. Thus;

Area of a circle is πr². A quadrant is a quarter of a circle. Thus;

Formula for Quadrant Area is; A = ¼πr²

A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.

Formula for the quadrant perimeter in the image given is;

P = 2πr/4 + 2r

P = πr/2 + 2r

B) When r is 5 cm;

A = ¼π(5)²

A = 19.63 cm²

P = π(5)/2 + 2(5)

P = 17.85 cm

C) when A is 100cm²:

¼πr² = 100

r² = 100 × 4/π

r² = 78.9358

r = √78.9358

r = 8.885 cm

D) when P = 50 cm.

50 = πr/2 + 2r

50 = (½π + 2)r

r = 50/(½π + 2)

r = 14 cm

6 0

3 years ago