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3 years ago

100 points nani?!?!

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28

First set of parenthesis:

2^8 = 256, 3^-5 = 0.00411522, 6^0 = 1

(256 * 0.00411522 * 1) = 1.05349794

1.05349794^-2 = 0.90101623

Second set of parenthesis:

3^-2 = 0.1111, 2^3 = 8

(0.111 / 8) = 0.0138

0.0138^4 = 0.00000003721088

Third set: 2^28 = 268435456

Final: 0.90101623 * 0.00000003721088 * 268435456 = 9

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28 = 9

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Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

11 months ago

Help pls haha also Merry Christmas

MArishka [77]

Answer:

x = √39

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Identify

Leg a = x

Leg b = 5

Hypotenuse c = 8

Step 2: Solve for x

Substitute [PT]: x² + 5² = 8²
Isolate x term: x² = 8² - 5²
Exponents: x² = 64 - 25
Subtract: x² = 39
Isolate x: x = √39

3 0

3 years ago

Read 2 more answers

To transmit information on the internet, large files are broken into packets of smaller sizes. Each packet has 1,500 bytes of in

erastova [34]

Answer: $x= 187.5p$

Step-by-step explanation:

Given : An equation relating packets to bytes of information : $b = 1,500p$ where p represents the number of packets and b represents the number of bytes of information.