3 years ago

100 points nani?!?!

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28

First set of parenthesis:

2^8 = 256, 3^-5 = 0.00411522, 6^0 = 1

(256 * 0.00411522 * 1) = 1.05349794

1.05349794^-2 = 0.90101623

Second set of parenthesis:

3^-2 = 0.1111, 2^3 = 8

(0.111 / 8) = 0.0138

0.0138^4 = 0.00000003721088

Third set: 2^28 = 268435456

Final: 0.90101623 * 0.00000003721088 * 268435456 = 9

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28 = 9

You might be interested in

What number can be use in the blank to make the equation true?<br><br> 3x + 1 = 3x +___

MAXImum [283]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write 0.300 in word form please

liraira [26]

0.300 in word form is three tenths

6 0

3 years ago

Read 2 more answers

Quadrilateral WXYZ has the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0).

AnnZ [28]

The length of side WX in Quadrilateral WXYZ is 3b units.

<h3>Coordinate plane</h3>

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

$AB=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Given the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0). The length of WX is:

$WX=\sqrt{(b-b)^2+(4b-b)^2}=3b$

The length of side WX in Quadrilateral WXYZ is 3b units.

Find out more on coordinate plane at: brainly.com/question/26100648

7 0

2 years ago

The earth is approximately 92,900,000 miles from the sun. If 1 mile = 1.61 x 103 m, what is the distance to the sun in meters?

Dmitriy789 [7]

Answer:

here you go

Step-by-step explanation:

5 0

3 years ago

Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form.

ololo11 [35]

Answer: Perimeter = 22*sqrt(2)

Area = 60.5 inches

Step-by-step explanation:

Simple a square has 4 equal sides.

It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

7 0

3 years ago

Read 2 more answers