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3 years ago

5,9,4,5,7,1,3,6 What is the median? A. 8 B. 1 C..5 D. 4.

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer: The median is 5.

Step-by-step explanation: If you add all the numbers up, you get 40. There are 8 numbers, so 40 divided by 8 is 5.

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Solve for x: |x − 2| + 10 = 12

raketka [301]

✯Let's solve this equation step-by-step!
✯is the question you've asked us today:
|x − 2| + 10 = 12

✯Add -10 to both sides:
|x−2|+10+−10=12+−10

✯Solve Absolute Value:
|x−2|=2

✯We know either:
x−2=2 or x−2=−2

(Possibility 1) x−2=2

(Add 2 to both sides) x−2+2=2+2

x=4

(Possibility 2) x−2=−2

(Add 2 to both sides) x−2+2=−2+2

x=0

✯So since we have gotten x=4 and x=0 you answer shall be:

B. x=4 and x=0

✯I hope this helps!✯

3 0

3 years ago

Read 2 more answers

If point c is inside

Fantom [35]

Answer:

If AVC∠+CVB∠ it would be AVB∠ so I'm guessing it would AVC∠

Step-by-step explanation:

My knowledge ;)

3 0

3 years ago

Read 2 more answers

There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror

RUDIKE [14]

Given:

Number of people bought tickets for comedy = $\frac{2}{5}$

Number of people bought tickets for horror = $\frac{1}{4}$

Number of people bought tickets for kids movie = $\frac{3}{10}$

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

Total number of tickets for comedy, horror and kids movie are = $(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )$

So,

$(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )$

LCM of 5,4,10 = 20

= $\frac{8+5+6}{20}$

= $\frac{19}{20}$

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = $1-\frac{19}{20}$

= $\frac{20-19}{20}$

= $\frac{1}{20}$

Hence,

The number of people who bought the tickets for action movie is $\frac{1}{20}$ .

7 0

4 years ago

A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr

Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.