Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
1) From building 1 to 2: 5 - (-3) = 8
2) From 2 to 3: 4 - (-5) = 9
3) From 3 to 4: 5 - (-3) = 8
4) From 4 to 1: 4 - (-5) = 9
Total: 8 + 9 + 8 + 9 = 34 units = 34*100 feet = 3400 feet.
Answer: 3400 feet
Answer:
12. -11
13. 2
Step-by-step explanation:
12. First recall the order of operations (BEDMAS): Brackets, Exponents, Division, Multiplication, Addition, Subtraction
For question 12 there is a division and its priority is before other operations in the equation so you must divide 16/-2 first which gives you -8.
From there because addition and subtraction is on the same level of order, you would do the question straight as it is shown (but replace 16/-2 with -8.
Your new equation is -10-8+7 = -11
13. follow the same as above using BEDMAS. It may help to look at it with additional brackets: ((-68)/(-4)) + ((5 x (-3))
- keep in mind there’s an addition between the two
Division and multiplication is on the same level in BEDMAS so first divide -68/-4 = 17
Second multiply 5 x -3 = -15
Now you can combine the two answers using addition: 17 + (-15) = 2
Answer:
Answer:
164.32 earth year
Step-by-step explanation:
distance of Neptune, Rn = 4.5 x 10^9 km
distance of earth, Re = 1.5 x 10^8 km
time period of earth, Te = 1 year
let the time period of Neptune is Tn.
According to the Kepler's third law
T² ∝ R³
Tn = 164.32 earth years
Thus, the neptune year is equal to 164.32 earth year.
Step-by-step explanation:
