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3 years ago

What is 5K +(-2k)-(-1)

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer:

5 K -2 k +1

Step-by-step explanation:

When there is a + in front of an expression in parentheses, the expression remains the same.

5 K -2 K - (-1)

When there is a - in front of an expression in parentheses, change the sign of each term in the expression

5 K - 2k +1

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Find the rate in the following problem. Round the answer to the nearest percent.

Anit [1.1K]

Answer: 75%

Step-by-step explanation:

150/200=.75

200 x .75=150

Now to turn .75 into a percent by moving the . over to the right two times.

75. or 75%

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3 years ago

"Which expression is NOT equivalent to the sum of 36 + 54?

german

Answer:

B equals 60 and 36+54 = 90

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3 years ago

Read 2 more answers

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

$\= x = 18.5$ , $\sigma = 5.15$

$15.505 < \mu < 21.495$

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

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3 years ago

egment AB falls on line 2x − 4y = 8. Segment CD falls on line 4x + 2y = 8. What is true about segments AB and CD?

jolli1 [7]

Answer:

The line segments AB and CD are perpendicular to each other.

Step-by-step explanation:

Segment AB falls on line 2x − 4y = 8.

Rearranging the equation into slope-intercept form we get, ............. (1)

Therefore, slope of the line segment AB is

Now, the segment CD falls on line 4x + 2y = 8.

Rearranging the equation into slope-intercept form we get, ............. (2)

Therefore, the slope of the line segment CD is, N = - 2

So, M × N =

Hence, we can conclude that the line segments AB and CD are perpendicular to each other

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4 years ago

Michael has just won some money on a game show! He has the option to take a lump sum payment of $700,000 now or get paid an annu

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Answer:

Answer is B, the nominal rate is 3% and the interest rate is 1%

Step-by-step explanation:

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3 years ago