Add 3 to both sides so that the equation becomes -2x^2 + 5x + 5 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √(5^2 - 4(-2)(5)) ] / ( 2(-2) )
x = [-5 ± √(25 - (-40) ) ] / ( -4 )
x = [-5 ± √(65) ] / ( -4)
x = [-5 ± sqrt(65) ] / ( -4 )
x = 5/4 ± -sqrt(65)/4
The answers are 5/4 + sqrt(65)/4 and 5/4 - sqrt(65)/4..
Answer:
be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house and I will be there
Answer: 1.4
Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.
So, its 2y=2.8
To solve this, you simply divide both sides of the equation by 2.
2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4
So, y=1.4
Cot=cos\sin
sec=1\cos
cosx\sinx÷1\cosx=
cos^2x\sinx=1-sin^2x\sinx=
1\sinx-sin^2x\sinx= 1/sinx-sinx
The correct answer is C. 5, 6, -7