Answer:
Point C
Step-by-step explanation:
If you retrieve 90 backwards, then you will get the point C.
Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
1/2(2x+6)
Substitute the one half to both of the numbers inside the parentheses.
1/2*2 is one which would just be x
1/2*6 is three
X+3
Answer:
The equation of a parallel line would be y = 2x + 4
Step-by-step explanation:
In order to find the equation of this line, we first have to note that paralell lines have same slopes. Therefore, since the original line has a slope of 2, we know the new line will have a slope of 2. Now we can use that information along with the given point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 8 = 2(x - 2)
y - 8 = 2x - 4
y = 2x + 4
