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natali 33 [55]
3 years ago
13

A cell has a 2\%2%2, percent salt concentration. It is placed into a solution containing a 2\%2%2, percent salt concentration. W

hat will happen to the cell?
Biology
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

Neither the solute nor the solvent (water) will move in any direction

Explanation:

Concentration of salt with in the cell = 2%

Concentration of salt of the solution in which the cell is placed is 2%

Since there is no change of concentration of salt with in cell and outside the cell. Hence, there will be no net movement of solute or solvent.

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What statement does NOT pertain to the cephalic phase of gastric secretion? (It controls the rate at which chyme enters the smal
egoroff_w [7]

Answer:

It controls the rate at which chyme enters the small intestine

Explanation:

Cephalic phase is one of the phase of gastric secretion (other two are gastric phase and intestinal phase) that begins even before food enters the oral cavity. Thinking of food stimulates the release of gastric juice via  parasympathetic nervous system). Food that enters the stomach also stimulates the secretion of gastric juice by parietal cells. Partially digested food directly activates  G cells (Enteroendocrine cells) to secrete gastrin which also stimulates the release of gastric juice.

8 0
4 years ago
Calculate mass % of nitrogen and oxygen in NO2.
sukhopar [10]

Explanation:

I'm not too sure but I would find the molar mass of nitrogen dioxide and then divide.

N - 14.01

O - 16.00

(14.01) + 2(16.00)

14 01 + 32.00 = 46.01

14.01 / 46.01 = 0.3044....

30.4%

32 / 46.01 = 0.6955....

69.6%

6 0
3 years ago
What can highly reduced molecules be used as?
igomit [66]
Reduction occurs when a molecule gains an electron or decreases its oxidation state.
4 0
3 years ago
Which one of the following is the correct sequence of events that correlates to the sequence of events of a nerve impulse?
quester [9]

Answer:

the correct sequence of the events happened during nerve impulse is (d): 2,1,4,3

Explanation:

Originally K+ ions remains inward the membranes while Na+ ions remains outward to maintain a resting potential of membrane.

Upon stimuli Sodium channels open on membrane and Na+ diffuses inward leading to the depolarization of membrane that is it becoming more positive due to Na+ and K+ ions.

To regain it polarized state or in repolarization state Potassium channels open and K+ begun to diffuse outward while Sodium channels gets closed and Na+ ions remains inside the membrane.

Potassium channels are not efficient as compared to Sodium Channels, so an excess amount of K+ion move outward so Hyperpolarization state achieved.

As the both ions are on the wrong side and will not be available for the next nerve impulse. Hence in Refractory period by the help of Na+/K+ pum, both ions move back to their original place and membrane achieve its resting membrane potential state.

8 0
3 years ago
Please help meeeeeee
Natali5045456 [20]

Answer:

help you with what theres no question here??

Explanation:

7 0
3 years ago
Read 2 more answers
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